Last month, your company sold 1,000 new watches. Past experience indicates that the probability that a new watch will need repair during its warranty period is 0.002. Let X be the number of watches among the 1,000 that will need repair during its warranty period. X is binomially distributed with n = 1,000 and p = 0.002. The distribution of X, however, can be approximated using a distribution with mean equal to Using this approximating distribution, we find that the probability of having at most two watches (in the batch of 1000) needing repair within their warranty periods equals . (Express this value precise to three decimal places, e.g., 0.281, 0.335, 0.721.)

Last month, your company sold 1,000 new watches. Past experience indicates that the probability that a new watch will need repair during its warranty period is 0.002. Let X be the number of watches among the 1,000 that will need repair during its warranty period. X is binomially distributed with n = 1,000 and p = 0.002. The distribution of X, however, can be approximated using a distribution with mean equal to Using this approximating distribution, we find that the probability of having at most two watches (in the batch of 1000) needing repair within their warranty periods equals . (Express this value precise to three decimal places, e.g., 0.281, 0.335, 0.721.)

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter9: Counting And Probability

Section9.3: Binomial Probability

Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...

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