Lattice energies and electron affinities are very difficult to measure experimentally. Fairly reliable theoretical values for lattice energies can be calculated from simple models. The Born-Haber cycle can then be used to estimate electron affinities. Use the data below to calculate the electron affinity of iodine (in kJ mol1), where a negative EA value indicates a favourable anion formation. Name of enthalpy change Value in kJ/mol Formation enthalpy of Cal2(s) -533.46 Lattice energy of Cal2 -2074 Sublimation enthalpy of Ca 177.7 First ionization energy of Ca 589.8 Second ionization energy of Ca 1145.4 Sublimation enthalpy of I2 62.44 Bond energy of l2 151.1

Lattice energies and electron affinities are very difficult to measure experimentally. Fairly reliable theoretical values for lattice energies can be calculated from simple models. The Born-Haber cycle can then be used to estimate electron affinities. Use the data below to calculate the electron affinity of iodine (in kJ mol1), where a negative EA value indicates a favourable anion formation. Name of enthalpy change Value in kJ/mol Formation enthalpy of Cal2(s) -533.46 Lattice energy of Cal2 -2074 Sublimation enthalpy of Ca 177.7 First ionization energy of Ca 589.8 Second ionization energy of Ca 1145.4 Sublimation enthalpy of I2 62.44 Bond energy of l2 151.1

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Chapter8: Electron Configurations And Periodicity

Section: Chapter Questions

Problem 8.119QP: The lattice energy of an ionic solid such as NaCl is the enthalpy change H for the process in which...

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The lattice energy of an ionic solid such as NaCl is the enthalpy change H for the process in which the solid changes to ions. For example, NaCl(s)Na+(g)+Cl(g)H=786kJ/mol Assume that the ionization energy and electron a affinity are H values for the processes defined by those terms. The ionization energy of Na is 496 kJ/mol. Use this, the electron affinity from Table 8.4, and the lattice energy of NaCl to calculate H for the following process: Na(g)+Cl(g)NaCl(s)
Determine the lattice energy for LiCl(s) given these data: Sublimation enthalpy of Li, 161 kJ/mol; IE, for Li, 520 kJ/mol; BE of Cl2(g), 242 kJ/mol; electron affinity of Cl, 349 kJ/mol; formation enthalpy of LiCl(s), 408.7 kJ/mol.
Consider a hypothetical ionic compound AB (comprised of A+ and B- ions). Given the following enthalpy data and using a Born-Haber cycle calculation, predict ΔHlattice in kJ mol-1. A(s) + B(s) → AB(s) ΔrH = -449 kJ mol-1 A(s) → A(g) ΔrH = 113 kJ mol-1 B(s) → B(g) ΔrH = 92 kJ mol-1 First ionization energy of A(g) = 529 kJ mol-1 Electron affinity enthalpy of B(g) (exothermic) = -345 kJ mol-1
Use the Born Haber cycle (show relevant steps) to determine the lattice energy of CsCl (s) from the following data:Hf 0 [CsCl(s)] = -442.8 kJ/mol; enthalpy of sublimation of Cesium is 78.2 kJ/mol; enthalpy of dissociation of Cl2 (g) = 243 kJ/mol Cl2 ; IE1 for Cs(g) = 375.7 kJ/mol; electron affinity enthalpy-EA1 for Cl(g) = -349kJ/mol
Use the data provided below to calculate the lattice energy of RbCl. Is this value greater or less than thelattice energy of NaCl? Explain.Electron affinity of Cl = –349 kJ/mol1st ionization energy of Rb = 403 kJ/molBond energy of Cl2 = 242 kJ/molSublimation energy of Rb = 86.5 kJ/molΔHf [RbCl (s)] = –430.5 kJ/mol
Use the Born-Haber cycle to calculate the lattice energy of KF. [The heat of sublimation of K is 91.6 kJ·mol−1 and ΔfH(KF) = −567.3 kJ·mol−1. Bond enthalpy for F2 is 158.8 kJ·mol−1. Other data may be found in the Ionization Energies Table and the Electron Affinities Table.]
Imagine a metallic element had been discovered and was named "Gondolium" (Gn).Gn was found to exhibit chemistry like that of an alkaline earth. Gn(s) + F2(g) → GnF2(s) Lattice energy for GnF2 -1950. kJ/mol First Ionization energy of Gn 450. kJ/mol Second Ionization energy of Gn 855 kJ/mol Electron affinity of F -327.8 kJ/mol Bond energy of F2 154 kJ/mol Enthalpy of sublimation (atomization) of Gn 195 kJ/mol Use the above data to calculate ΔH°f for gondolium fluoride.
Use the Born Haber cycle (show relevant steps) to determine the lattice energy of CsCl (s) from the following data: ΔHf°[CsCl(s)] = -442.8 kJ/mol; enthalpy of sublimation of Cesium is 78.2 kJ/mol; enthalpy of dissociation of Cl2 (g) = 243 kJ/mol Cl2 ; IE1 for Cs(g) = 375.7 kJ/mol; electron affinityenthalpy-EA1 for Cl(g) = -349kJ/mol.
Suppose a chemist discovers a new metallic element and names it "Xercisium" (Xr). Xr exhibits chemical behaviour similar to an alkaline earth. Xr(s) + Cl2(g) → XrCl2(s) Lattice energy for XrCl2 -2020. kJ/mol First Ionization energy of Xr 500. kJ/mol Second Ionization energy of Xr 950. kJ/mol Electron affinity of Cl -348.7 kJ/mol Bond energy of Cl2 239 kJ/mol Enthalpy of sublimation (atomization) of Xr 200. kJ/mol Use the above data to calculate ΔH°f for Xercisium chloride.
Using simitar Born-Haber cycle to the above it is possible to calculate the enthalpies of formation of MgCl and MgC13. In order to do so an estimated value for one energy change in the cycle must be used. Which energy change is this?
The work function (Φ) of a metal is the minimum energy needed to remove an electron from its surface. (a) Is it easier toremove an electron from a gaseous silver atom or from the sur-face of solid silver (Φ=7.59X10⁻¹⁹J; IE =731 kJ/mol)? (b) Explain the results in terms of the electron-sea model ofmetallic bonding
Use the periodic table to arrange the following elements in order of increasing firstionisation energy: P, S, O. Give a brief explanation why you chose this arrangement.

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