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lculate ∆H for the reaction 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (g), from the following data. 1. N2 (g) + O2 (g) → 2NO (g) ∆H = -180.5 kJ 2. N2 (g) + 3H2 (g) → 2 NH3 (g) ∆H = -91.8 kJ 3. 2H2 (g) + O2 (g) → 2H2O (g) ∆H

lculate ∆H for the reaction 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (g), from the following data. 1. N2 (g) + O2 (g) → 2NO (g) ∆H = -180.5 kJ 2. N2 (g) + 3H2 (g) → 2 NH3 (g) ∆H = -91.8 kJ 3. 2H2 (g) + O2 (g) → 2H2O (g) ∆H

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
Section: Chapter Questions
Problem 82QRT
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Calculate ∆H for the reaction 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (g), from the following data.

1. N2 (g) + O2 (g) → 2NO (g) ∆H = -180.5 kJ

2. N2 (g) + 3H2 (g) → 2 NH3 (g) ∆H = -91.8 kJ

3. 2H2 (g) + O2 (g) → 2H2O (g) ∆H = -483.6 kJ

6. Calculate AH for the reaction 4NH3 (g) + 502 (g) → 4NO (g) + 6H20 (g), from the following data. 1. N2 (g) + 02 (g) → 2NO (g) 2. N2 (g) + 3H2 (g) → 2 NH3 (g) 3. 2H2 (g) + 02 (g) → 2H20 (g) AH = -180.5 k AH = -91.8 kJ AH = -483.6 kJ
Transcribed Image Text:6. Calculate AH for the reaction 4NH3 (g) + 502 (g) → 4NO (g) + 6H20 (g), from the following data. 1. N2 (g) + 02 (g) → 2NO (g) 2. N2 (g) + 3H2 (g) → 2 NH3 (g) 3. 2H2 (g) + 02 (g) → 2H20 (g) AH = -180.5 k AH = -91.8 kJ AH = -483.6 kJ
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