Leel, bying compare the = 36 specimens of commercial steel y = 58.5. Because the high-purity steel is more expensive, its use for a certain application can be justified only if its fracture toughness exceeds that of commercial-purity steel by more than 5. Suppose that both oughness distributions are normal. (a) Assuming that ₁1.4 and ₂ = 1.0, test the relevant hypotheses using a = 0.001. (Use ₁-₂, where is the average toughness for high-purity steel and ₂ is the average toughness for commercial steel.) State the relevant hypotheses. H₂H₁ H₂ = 5 H₂H₂-H₂ <5 Ho: M₁ M₂=5 Hg: H₂-H₂>5 ⒸH₂²H₁-H₂ = 5 H₂H₁-H₂ 55 o Hỏi My k = 5 Ha: H1 -H2 +5 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value= State the conclusion in the problem context. O Reject Ho. The data suggests that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5. Fail to reject Ho. The data does not suggest that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5. O Fail to reject Ho. The data suggests that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5. O Reject Ho. The data does not suggest that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5. (b) Compute for the test conducted in part (a) when #₁ - #₂ = 6. (Round your answer to four decimal places.)
Leel, bying compare the = 36 specimens of commercial steel y = 58.5. Because the high-purity steel is more expensive, its use for a certain application can be justified only if its fracture toughness exceeds that of commercial-purity steel by more than 5. Suppose that both oughness distributions are normal. (a) Assuming that ₁1.4 and ₂ = 1.0, test the relevant hypotheses using a = 0.001. (Use ₁-₂, where is the average toughness for high-purity steel and ₂ is the average toughness for commercial steel.) State the relevant hypotheses. H₂H₁ H₂ = 5 H₂H₂-H₂ <5 Ho: M₁ M₂=5 Hg: H₂-H₂>5 ⒸH₂²H₁-H₂ = 5 H₂H₁-H₂ 55 o Hỏi My k = 5 Ha: H1 -H2 +5 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value= State the conclusion in the problem context. O Reject Ho. The data suggests that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5. Fail to reject Ho. The data does not suggest that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5. O Fail to reject Ho. The data suggests that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5. O Reject Ho. The data does not suggest that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5. (b) Compute for the test conducted in part (a) when #₁ - #₂ = 6. (Round your answer to four decimal places.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:An experiment was performed to compare the fracture toughness of high-purity 18 Ni maraging steel with commercial-purity steel of the same type. For m = 34 specimens, the sample average toughness was x = 64.3 for the high-purity steel, whereas for
n = 36 specimens of commercial steel y = 58.5. Because the high-purity steel is more expensive, its use for a certain application can be justified only if its fracture toughness exceeds that of commercial-purity steel by more than 5. Suppose that both
toughness distributions are normal.
(a) Assuming that o₁ = 1.4 and ₂ = 1.0, test the relevant hypotheses using a = 0.001. (Use μ₁-₂, where μ₁ is the average toughness for high-purity steel and ₂ is the average toughness for commercial steel.)
State the relevant hypotheses.
о но 1-2=5
H₂H₁ H₂ < 5
но 1-2=5
H₂: M₁ - H₂> 5
о но: 1 - 2 = 5
H₂: M₁-M₂ ≤ 5
| Ho: M₁ M₂=5
H₂: M₂ M₂ #5
Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.)
Z =
P-value=
State the conclusion in the problem context.
O Reject Ho. The data suggests that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5.
ⒸFail to reject Ho. The data does not suggest that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5.
O Fail to reject Ho. The data suggests that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5.
O Reject Ho. The data does not suggest that the fracture toughness of high-purity steel exceeds that of commercial-purity steel by more than 5.
(b) Compute for the test conducted in part (a) when #₁ #₂ = 6. (Round your answer to four decimal places.)
B =
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