Let a > 0 be a real number and considerthe family of functions ƒ(x) = sin ax on the interval [0, ∏/a].a. Graph ƒ, for a = 1, 2, and 3.b. Let g(a) be the area of the region bounded by the graphof ƒ and the x-axis on the interval [0, ∏/a]. Graph g for0 < a < ∞ . Is g an increasing function, a decreasingfunction, or neither?
Let a > 0 be a real number and considerthe family of functions ƒ(x) = sin ax on the interval [0, ∏/a].a. Graph ƒ, for a = 1, 2, and 3.b. Let g(a) be the area of the region bounded by the graphof ƒ and the x-axis on the interval [0, ∏/a]. Graph g for0 < a < ∞ . Is g an increasing function, a decreasingfunction, or neither?
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 52E
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Question
Let a > 0 be a real number and consider
the family of functions ƒ(x) = sin ax on the interval [0, ∏/a].
a. Graph ƒ, for a = 1, 2, and 3.
b. Let g(a) be the area of the region bounded by the graph
of ƒ and the x-axis on the interval [0, ∏/a]. Graph g for
0 < a < ∞ . Is g an increasing function, a decreasing
function, or neither?
Expert Solution
Step 1
Given that family of functions is ƒ(x) = sin ax, on the interval and .
Answer(a):
For , the function becomes ƒ(x) = sin x.
So, the graph of the function ƒ(x) = sin x in the interval is:
Step 2
For , the function becomes ƒ(x) = sin 2x.
So, the graph of the function ƒ(x) = sin 2x in the interval is:
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