Let C be the arc of the curve y = f(x) between the points P(p, f(p)) and Q(g, f(g)) and let R be the region bounded by C, by the line y = mx + b (which lies entirely below C), and by the perpendiculars to the line from P and Q. %3D YA y f(x) R. P C y=mx+b Au 3, hat the area of R is - mx - b][1 + mf'(x)] dx [Hint: This formula can be verified by subtracting areas, but it will be helpful throughout the project to derive it by first approximating the area using rectangles perpendicular to the line, as shown in the following figure. Use the figure to help express Au in terms of Ax.] tangent to C at (xi, f(x;)) y=mx+b Au Ax

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section: Chapter Questions
Problem 12T
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see picture question 3.

Let C be the arc of the curve y = f(x) between the points P(p, f(p)) and Q(g, f(g)) and let R
be the region bounded by C, by the line y = mx + b (which lies entirely below C), and by the
perpendiculars to the line from P and Q.
%3D
YA
y f(x)
R.
P C
y=mx+b
Au
3, hat the area of R is
- mx - b][1 + mf'(x)] dx
[Hint: This formula can be verified by subtracting areas, but it will be helpful throughout the
project to derive it by first approximating the area using rectangles perpendicular to the line,
as shown in the following figure. Use the figure to help express Au in terms of Ax.]
tangent to C
at (xi, f(x;))
y=mx+b
Au
Ax
Transcribed Image Text:Let C be the arc of the curve y = f(x) between the points P(p, f(p)) and Q(g, f(g)) and let R be the region bounded by C, by the line y = mx + b (which lies entirely below C), and by the perpendiculars to the line from P and Q. %3D YA y f(x) R. P C y=mx+b Au 3, hat the area of R is - mx - b][1 + mf'(x)] dx [Hint: This formula can be verified by subtracting areas, but it will be helpful throughout the project to derive it by first approximating the area using rectangles perpendicular to the line, as shown in the following figure. Use the figure to help express Au in terms of Ax.] tangent to C at (xi, f(x;)) y=mx+b Au Ax
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