Let ɛr1 = 2.26 for 0

We need to find out equivalent capacitance .

Answered: Let Er1 = 2.26 for 0 < y< 2 mm, ɛR2 =…

Engineering

Electrical Engineering

Let Er1 = 2.26 for 0 < y< 2 mm, ɛR2 = 2.31 for 2 < y< 2.7 mm, and ER3 = 4.31 for 2.7

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter19: Capacitors

Section: Chapter Questions

Problem 1RQ: 1. What is the dielectric?

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Graph theory

It is that part of network analysis where the configuration is called graph or structure of the network system when all of the elements (e.g., R, L, and C) in a network system are substituted with lines having circles/rings or dots across both endpoints. The study of the solution of the networks and circuits with the help of graphs is known as graph theory. The objective is to know the mathematics behind the network analysis.

Question

Let ɛr1 = 2.26 for 0 <y< 2 mm, Er2 = 2.31 for 2 < y< 2.7 mm, and ɛr3 = 4.31 for 2.7 <y< 3.8 mm. Conducting surfaces are present
at y = 0 and y = 3.8 mm. Calculate the capacitance per square meter of surface area (in nF).
Round your answer to 2 decimal places.
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