Question
Asked Dec 2, 2019
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Let F(X)=400x-11x2-6. Find the maximum value of f to four decimal places graphically.

The maximum value of f is?

 

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Expert Answer

Step 1

The given function is,

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F (x) =-11x + 400x – 6. Observe that the given equation is in the form of quadratic equation. That is, a = -11, b = 400 and c=-6. It is known that, the maximum value occurs at x =- 2a 400 400 X =-- 2(-11) 22 200 11

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Step 2

In order to find the maximum value, substitute the...

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200 F 11 200 -11 200 + 400 -6 11 40, 000 80,000 -6 11 11 -40,000 + 80,000 – 66 11 39,934 = 3630.36363 11 = 3630.3636 200 Thus, the maximum value offis 3630.3636 at x =- 11

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