let i = 0; (i 10) { console. log (i);
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4. Complete the JavaScript code to print natural numbers from 0 to 10.
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- #9. a program to implement hashcode and equals..Each recursion causes a new activation frame to be placed on the stack.true of false?/** Iluustration of RecursiveTask*/import java.util.concurrent.ExecutionException;import java.util.concurrent.ForkJoinPool;import java.util.concurrent.RecursiveTask; public class SumWithPool{ public static void main(String[] args) throws InterruptedException, ExecutionException { //get the number of avaialbe CPUs int nThreads = Runtime.getRuntime().availableProcessors(); System.out.println("Available CPUs: " + nThreads); //create an array of data int n = 10; //initital data size if(args.length > 0) // use the user given data size n = Integer.parseInt(args[0]); int[] numbers = new int[n]; for(int i = 0; i < numbers.length; i++) { numbers[i] = i; } ForkJoinPool forkJoinPool = new ForkJoinPool(nThreads); Sum s = new Sum(numbers,0,numbers.length); long startTime = System.currentTimeMillis(); //start timer Long result = forkJoinPool.invoke(s); long endTime =…
- Please convert Mutual Recursion to Java. See attached image. Thank you.Interpreter.java is missing these methods in the code so make sure to add them: -print, printf: Exist, marked as variadic, call Java functions -getline and next: Exist and call SplitAndAssign -gsub, match, sub, index, length, split, substr, tolower, toupper: Exist, call Java functions, correct return Below is interpreter.java import java.util.ArrayList; import java.util.HashMap; import java.util.List; public class Interpreter { private HashMap<String, InterpreterDataType> globalVariables; private HashMap<String, FunctionDefinitionNode> functions; private class LineManager { private List<String> lines; private int currentLineIndex; public LineManager(List<String> inputLines) { this.lines = inputLines; this.currentLineIndex = 0; } public boolean splitAndAssign() { if (currentLineIndex < lines.size()) { String currentLine = lines.get(currentLineIndex);…- Give Java Code that finds the number of children using the sequential representation, Linked Implementations Using Array of Child Pointers implementation, linked implementation left-child/right-sibling.
- Explain Divide and Conquer Approach with help of codeModify the generic Pair.java class in two ways: Make it so that both values have the same type Add a method swap that swaps the first and second elements of the pair Examples:Pair<Integer> intPair = new Pair<>(17, 19);intPair.getFirst(); // returns 17intPair.getSecond(); // returns 19intPair.swap();intPair.getFirst(); // returns 19intPair.getSecond(); // returns 17Pair<String> strPair = new Pair<>("Erick", "Valdez");strPair.getFirst(); // returns "Erick"strPair.getSecond(); // returns "Valdez"strPair.swap();strPair.getFirst(); // returns "Valdez"strPair.getSecond(); // returns "Erick" Pair.java /*** This class collects a pair of elements of different types.*/public class Pair<T, S> {private T first;private S second;/*** Constructs a pair containing two given elements.* * @param firstElement the first element* @param secondElement the second element*/public Pair(T firstElement, S secondElement) {first = firstElement;second = secondElement;}/*** Gets…Consider the following hashCode() implementation forString, which was used in early versions of Java:public int hashCode(){ int hash = 0; int skip = Math.max(1, length()/8); for (int i = 0; i < length(); i += skip) hash = (hash * 37) + charAt(i); return hash;}Explain why you think the designers chose this implementation.se
- Write a recursive method in Java that displays a portion of a given array backward. Consider the last entry in the portion first.Given the following function, what happens if a[] contains just one element that doesn't match val? int binarySearch(int a[], int first, int last, int val){ if (first > last) return -1; int middle = (first + last) / 2; if (a[middle] == val) return middle; if (a[middle] < val) return binarySearch(a, middle+1, last, val); else return binarySearch(a, first, middle-1, val);} Group of answer choices binarySearch never calls itself again and terminates (recursion never happens) binarySearch calls itself once then terminates (recursion happens once) binarySearch calls itself twice then terminates (recursion happens twice) binarySearch calls itself 3 times then terminates (recursion happens 3 times)Go program using generics Output True False