Let R, = = 1, 1 + for each positive integer i. (Enter your answers using interval notation.) (a) 7 ÚR - [12] [1,2] i = 1 (b) 7 =ם i = 1 [*+] (c) Are R,, R2, Rgi ,R, mutually disjoint? Why or why not? ... O Yes, because the intersection of the sets R,, R,, R, ..., R, is empty. 2. O Yes, because no two of the sets R,, R,, R31 R, have any elements in common. O Yes, because the union of the sets R,, R2, R31 R, is empty. .... O No, because the sets R,, R2' R31 R, are disjoint. No, because no two of the sets R,, R,, R3, R, are disjoint. 1' (d) U R; = (е) п n R; = i = 1 (f) U R, = i = 1 (g) 00 n R; = i = 1
Let R, = = 1, 1 + for each positive integer i. (Enter your answers using interval notation.) (a) 7 ÚR - [12] [1,2] i = 1 (b) 7 =ם i = 1 [*+] (c) Are R,, R2, Rgi ,R, mutually disjoint? Why or why not? ... O Yes, because the intersection of the sets R,, R,, R, ..., R, is empty. 2. O Yes, because no two of the sets R,, R,, R31 R, have any elements in common. O Yes, because the union of the sets R,, R2, R31 R, is empty. .... O No, because the sets R,, R2' R31 R, are disjoint. No, because no two of the sets R,, R,, R3, R, are disjoint. 1' (d) U R; = (е) п n R; = i = 1 (f) U R, = i = 1 (g) 00 n R; = i = 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter1: Introduction To Algebra
Section1.4: Translating Words Into Symbols
Problem 6MRE
Related questions
Question
Part D
![Let R; =
<x <1 +
1, 1 +
for each positive integer i. (Enter your answers using interval notation.)
(a)
7
UR,:
[1,2]
=
i = 1
(b)
7
[14]
n R; =
i = 1
(c) Are R,, R21 R31
R, mutually disjoint? Why or why not?
O Yes, because the intersection of the sets R,, R,, R,
R, is empty.
.../
O Yes, because no two of the sets R,, R,, R31
R, have any elements in common.
O Yes, because the union of the sets R,, R2, R31
R, is empty.
O No, because the sets R,, R2, R3.
R, are disjoint.
....
O No, because no two of the sets R,, R,, R3, ..., R, are disjoint.
(d)
U R; =
i = 1
(e)
n
n R; =
i = 1
(f)
U R; =
i = 1
(g)
00
n R; =
i = 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd16c46a0-d8b3-4c49-8249-7270f2b9ceb6%2F76406e2f-3544-40c3-bc31-e97e28fe3c4a%2Fu11ck1_processed.png&w=3840&q=75)
Transcribed Image Text:Let R; =
<x <1 +
1, 1 +
for each positive integer i. (Enter your answers using interval notation.)
(a)
7
UR,:
[1,2]
=
i = 1
(b)
7
[14]
n R; =
i = 1
(c) Are R,, R21 R31
R, mutually disjoint? Why or why not?
O Yes, because the intersection of the sets R,, R,, R,
R, is empty.
.../
O Yes, because no two of the sets R,, R,, R31
R, have any elements in common.
O Yes, because the union of the sets R,, R2, R31
R, is empty.
O No, because the sets R,, R2, R3.
R, are disjoint.
....
O No, because no two of the sets R,, R,, R3, ..., R, are disjoint.
(d)
U R; =
i = 1
(e)
n
n R; =
i = 1
(f)
U R; =
i = 1
(g)
00
n R; =
i = 1
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