let (sn) be a convergent sequence, and suppose lim sn > a. Prove there exists a number N such that n > N implies sn >a.
let (sn) be a convergent sequence, and suppose lim sn > a. Prove there exists a number N such that n > N implies sn >a.
Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter2: The Integers
Section2.2: Mathematical Induction
Problem 55E: The Fibonacci sequence fn=1,1,2,3,5,8,13,21,... is defined recursively by f1=1,f2=1,fn+2=fn+1+fn for...
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I have a question regarding limits:
let (sn) be a convergent sequence, and suppose lim sn > a. Prove there exists a number N such that n > N implies sn >a.
I started by saying lim sn = L > a, and I'm assuming we want to prove by contradiction ( sn < a, then lim sn < a), but I get to the definition
|sn - L| and get lost. Where do I go from here? Thanks!
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