best test of the simple hypothesis Ho : 01 = 0 = 0, 02 = 02 = 1 against the ive simple hypothesis H1 : 01 = 0 = 1, 02 = 0% = 4.
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- The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of SiO2 in a sample is normally distributed with ? = 0.32 and that x = 5.21. (Use ? = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5?State the appropriate null and alternative hypotheses. H0: ? = 5.5Ha: ? ≠ 5.5H0: ? = 5.5Ha: ? ≥ 5.5 H0: ? = 5.5Ha: ? < 5.5H0: ? = 5.5Ha: ? > 5.5 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is sufficient evidence to conclude that the true average percentage differs from the desired percentage.Reject the null hypothesis. There is sufficient evidence…If a 95% CI for mu is (1.05, 3.95) when sigma is known a Ztest at alpha=0.05 with a Null hypothesis: mu=1 would reject the Alternative hypothesis True or FalseA researcher predicts that scores in treatment A will be higher than scores in treatment B. If the mean for the 10 participants in treatment A is 4 points higher than the mean for the 10 participants in treatment B and the data produced t = 2.095 What decision should be made? Choose one a. With an alpha = .05 reject the null for either a one tail or two tails b. With an alpha = .05 fail to reject the null for either a one tail or two tails c. With an alpha = .05 reject the null for one tail but fail to reject with two tails d. With an alpha = .05 reject the null for two tails but fail to reject for a one tail
- 25. The State of California claims the population average of the amount of ice cream each Californian eats in the month of September is 6.85 pints with population standard deviation of 1.35 pints. An SRS of 500 Californians resulted in a sample average of 6.75 pints eaten per person in the month of September . At alpha=0.05, is there evidence to support the State of California's claim that Californians eat an average of 6.85 pints of ice cream in the month of September? Write a conclusion using the context of the problem.If X1, X2, and X3 constitute a random sample of sizen = 3 from a Bernoulli population, show that Y =X1 + 2X2 + X3 is not a sufficient estimator of θ. (Hint:Consider special values of X1, X2, and X3.)23. The State of California claims the population average of the amount of ice cream each Californian eats in the month of September is 6.85 pints with population standard deviation of 1.35 pints. An SRS of 500 Californians resulted in a sample average of 6.75 pints eaten per person in the month of September At alpha = 0.05 , is there evidence to support the State of California's claim that Californians eat an average of 6.85 pints of ice cream in the month of September? Find the p-value ?
- In a hypothesis test with hypotheses Ho: μ ≤ 54 and H1: μ > 54, a random sample of 24 elements selected from the population produced a mean of 58.6 and a standard deviation of 13.4. The test is to be made at the 10% significance level. Assume the population is normally distributed. What is the critical value of t ?Assume we wanted to show that the true proportion of virginica iris seeds that fail to germinate is less than 20%. Let's say we tested at an alpha of 0.05, and found a p-vale of 0.082. Which of the following would be an appropriate conclusion and interpretation? A) With an alpha of 0.05, and a p-value of 0.082, we fail to reject the null and state we have insufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. B) With an alpha of 0.05, and a p-value of 0.0082, we reject the null and state we have sufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. C) With an alpha of 0.05, and a p-value of 0.082, we reject the null and state we have sufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. D) With an alpha of 0.05, and a p-value of 0.082, we fail to reject the null and state…A researcher obtains t=2.25 for a repeated measures study using a sample of n=10 participants. Based on this t value, what is the correct decision for a two- tail test at .05 and .01 alpha level?
- .A sample of 9 measurements, randomly selected from a normally distributed population, resulted in x= 2.6, and s= 0.9 Conduct a hypothesis test to verify the claim that the population mean is greater than 2.5 . Use a=.05A test of H0H0:μ=1:μ=1 against HaHa:μ>1:μ>1 has test statistic zz = 1.74. Answer "Yes/Y" or "No/N" to the following questions. Is this test significant at the 2.5% level (αα = 0.025)? Is it significant at the 0.5% level (αα = 0.005)?24. The State of California claims the population average of the amount of ice cream each Californian eats in the month of September is 6.85 pints with population standard deviation of 1.35 pints. An SRS of 500 Californians resulted in a sample average of 6.75 pints eaten per person in the month of September. At alpha = 0.05 , is there evidence to support the State of California's claim that Californíans eat an average of 6.85 pints of ice cream in the month of September? True or False : Since the p-value is greater than alpha we fail to reject the null hypothesis. True False