Let Z = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows: R = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (2, 2), (3, 0), (3, 3)}, S = {(0, 0), (0, 2), (0, 3), (2, 3)}, %3D T = {(0, 1), (2, 3)}. %3D I has . properties Seç. S has . properties Seç. R has . properties Seç. The equivalance relation is: Seç.

Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Linear Transformations
Section6.CR: Review Exercises
Problem 65CR
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Let Z = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows:
R = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (2, 2), (3, 0), (3, 3)},
%3D
S= {(0, 0), (0, 2), (0, 3), (2, 3)},
%3D
T = {(0, 1), (2, 3)}.
I has . properties
Seç.
S has . properties
Seç.
R has . properties
Seç.
The equivalance relation is:
Seç.
Transcribed Image Text:Let Z = {0, 1, 2, 3} and the relations R, S, and T on Z are as follows: R = {(0, 0), (0, 1), (0, 3), (1, 0), (1, 1), (2, 2), (3, 0), (3, 3)}, %3D S= {(0, 0), (0, 2), (0, 3), (2, 3)}, %3D T = {(0, 1), (2, 3)}. I has . properties Seç. S has . properties Seç. R has . properties Seç. The equivalance relation is: Seç.
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