Let's examine the mean of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 by drawing samples from these values, calculating the mean of each sample, and then considering the sampling distribution of the mean. To do this, suppose you perform an experiment in which you roll an eight-sided die two times (or equivalently, roll two eight-sided dice one time) and calculate the mean of your sample. Remember that your population is the numbers 1, 2, 3, 4, 5, 6, 7, and 8. The true mean (u) of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 is The number of possible different samples (each of size n = 2) is the number of possibilities on the first roll (8) times the number of possibilities on the second roll (also 8), or 8(8) = 64. If you collected all of these possible samples, the mean of your sampling distribution of means (UM) would equal and the standard deviation of your sampling distribution of means (that is, the standard error or GM) would be The following chart shows the sampling distribution of the mean (M) for your experiment. Suppose you do this experiment once (that is, you roll the die two times). Use the chart to determine the probability that the mean of your two rolls is equal to the true mean, or P(M = µ), is_ The probability that the mean of your two rolls is greater than 1.5, or P(M > 1.5), is Frequency 8 2 and the true standard deviation (c) is 1 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 50 M 5.5 60 6.5 7.0 7.5 8.0

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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Let's examine the mean of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 by drawing samples from these values, calculating the mean of each sample, and
then considering the sampling distribution of the mean. To do this, suppose you perform an experiment in which you roll an eight-sided die two times
(or equivalently, roll two eight-sided dice one time) and calculate the mean of your sample. Remember that your population is the numbers 1, 2, 3, 4,
5, 6, 7, and 8.
The true mean (p) of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 is
The number of possible different samples (each of size n = 2) is the number of possibilities on the first roll (8) times the number of possibilities on the
second roll (also 8), or 8(8) = 64. If you collected all of these possible samples, the mean of your sampling distribution of means (HM) would equal
, and the standard deviation of your sampling distribution of means (that is, the standard error or GM) would be
The following chart shows the sampling distribution of the mean (M) for your experiment. Suppose you do this experiment once (that is, you roll the
die two times). Use the chart to determine the probability that the mean of your two rolls is equal to the true mean, or P(M = μ), is
▼. The
probability that the mean of your two rolls is greater than 1.5, or P(M > 1.5), is
Frequency
9
8
7
6
5
K
3
2
1
0
, and the true standard deviation (o) is
35
1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0 6.5
M
7.0 7.5 8.0
Transcribed Image Text:Let's examine the mean of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 by drawing samples from these values, calculating the mean of each sample, and then considering the sampling distribution of the mean. To do this, suppose you perform an experiment in which you roll an eight-sided die two times (or equivalently, roll two eight-sided dice one time) and calculate the mean of your sample. Remember that your population is the numbers 1, 2, 3, 4, 5, 6, 7, and 8. The true mean (p) of the numbers 1, 2, 3, 4, 5, 6, 7, and 8 is The number of possible different samples (each of size n = 2) is the number of possibilities on the first roll (8) times the number of possibilities on the second roll (also 8), or 8(8) = 64. If you collected all of these possible samples, the mean of your sampling distribution of means (HM) would equal , and the standard deviation of your sampling distribution of means (that is, the standard error or GM) would be The following chart shows the sampling distribution of the mean (M) for your experiment. Suppose you do this experiment once (that is, you roll the die two times). Use the chart to determine the probability that the mean of your two rolls is equal to the true mean, or P(M = μ), is ▼. The probability that the mean of your two rolls is greater than 1.5, or P(M > 1.5), is Frequency 9 8 7 6 5 K 3 2 1 0 , and the true standard deviation (o) is 35 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0 6.5 M 7.0 7.5 8.0
Fertical at a = 0.01 is
Now evaluate the null hypothesis that the population means for all treatments are equal. At a significance level of a = 0.01, the null hypothesis is
You find that you
conclude that the direction that the stroller faces influences a child's expressive vocabulary at 18
months.
Now you decide to use a t test to test the hypothesis that there is no difference between the groups. The estimated standard error (SM1 M2) is 5.13,
so the t test statistic is
Use the following tool to find the critical regions for a = 0.01.
t Distribution
Degrees of Freedom - 21
-3.0
-2.0
2500
-1.0
5000
5000
5000
0.0
-0.686 0.000 0.686
2500
1.0
2.0
3.0
Now use the tool to evaluate the null hypothesis. At a significance level of a = 0.01, the null hypothesis is
conclude that the direction the stroller faces influences a child's expressive vocabulary at 18 months.
1
The critical t-scores (the values for t-scores that separate the tails from the main body of the distribution, forming the critical regions) are
You find that you
When you evaluated the mean difference from the independent-measures study comparing only two samples, the ANOVA and the t test resulted in
conclusion.
Transcribed Image Text:Fertical at a = 0.01 is Now evaluate the null hypothesis that the population means for all treatments are equal. At a significance level of a = 0.01, the null hypothesis is You find that you conclude that the direction that the stroller faces influences a child's expressive vocabulary at 18 months. Now you decide to use a t test to test the hypothesis that there is no difference between the groups. The estimated standard error (SM1 M2) is 5.13, so the t test statistic is Use the following tool to find the critical regions for a = 0.01. t Distribution Degrees of Freedom - 21 -3.0 -2.0 2500 -1.0 5000 5000 5000 0.0 -0.686 0.000 0.686 2500 1.0 2.0 3.0 Now use the tool to evaluate the null hypothesis. At a significance level of a = 0.01, the null hypothesis is conclude that the direction the stroller faces influences a child's expressive vocabulary at 18 months. 1 The critical t-scores (the values for t-scores that separate the tails from the main body of the distribution, forming the critical regions) are You find that you When you evaluated the mean difference from the independent-measures study comparing only two samples, the ANOVA and the t test resulted in conclusion.
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