Lets start with the medical components. We need to determine how many units of the syringe connections can be made out of one metric ton of PEI, or around 2205 lbs of the plastic. Starting material - PEI 1 metric ton = 2205 lbs Calculation for number of units of each component: total weight of starting material PEI x Products Medical components Stopcock with Luer Connection, 1-way, male lock Products Medical components unit weight 2.72 g = 3/500 lbs Stopcock with Luer Connection, 1-way, male lock unit weight 2.72 g = 3/500 lbs 1 weight of unit of component This calculation assumes all starting material is used during the production of the components. Female Luer Lock 3/16" unit weight 0.63 g = 7/5000 lbs 1 unit of medical component total units of medical componen If necessary round to the closest whole number Units = Female Luer Lock 3/16" unit weight 0.63 g = 7/5000 lbs Determine the number of units for each medical component before moving forw Units =

Lets start with the medical components. We need to determine how many units of the syringe connections can be made out of one metric ton of PEI, or around 2205 lbs of the plastic. Starting material - PEI 1 metric ton = 2205 lbs Calculation for number of units of each component: total weight of starting material PEI x Products Medical components Stopcock with Luer Connection, 1-way, male lock Products Medical components unit weight 2.72 g = 3/500 lbs Stopcock with Luer Connection, 1-way, male lock unit weight 2.72 g = 3/500 lbs 1 weight of unit of component This calculation assumes all starting material is used during the production of the components. Female Luer Lock 3/16" unit weight 0.63 g = 7/5000 lbs 1 unit of medical component total units of medical componen If necessary round to the closest whole number Units = Female Luer Lock 3/16" unit weight 0.63 g = 7/5000 lbs Determine the number of units for each medical component before moving forw Units =

Introductory Chemistry: An Active Learning Approach

6th Edition

ISBN:9781305079250

Author:Mark S. Cracolice, Ed Peters

Publisher:Mark S. Cracolice, Ed Peters

Chapter3: Measurement And Chemical Calculations

Section: Chapter Questions

Problem 128E: In Active Example 3-29 you calculated that you would have to work six weeks to earn enough money to...

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In Active Example 3-29 you calculated that you would have to work six weeks to earn enough money to buy a 1082.49 television. You would be working five shifts of four hours each at 9.25/hr. But, alas, when you received your first pay check, you found that exactly 23 of your earnings had been withheld for social security, federal and state income taxes, and workers compensation insurance. Taking these into account, how many weeks will it take to earn the 1082.49?
15.4a 3 please. 0.166 was incorrect.
How do you convert 18.8 CP2/TM3 to YY2/ZW3? Use the folowing inequalities: 1CP=2.104 BX, *Bx=4 YY, 1TM=7.1088DD, 1DD=4.966ZW. When writing out the answer leave out the units.
In biological systems, enzymes are used to accelerate the rates of certain biological reactions. Glucoamylase is an enzyme that aids in the conversion of starch to glucose (a sugar that cells use for energy). Experiments show that 1 μg mol of glucoamylase in a 4% starch solution results in a production rate of glucose of 0.6 μg mol/(mL)(min). Determine the production rate of glucose for this system in units of lb mol/(ft3)(day). A. 0.0015 lb mol/(ft3)(day) B. 0.0315 lb mol/(ft3)(day) C. 0.0539 lb mol/(ft3)(day) D. 0.3569 lb mol/(ft3)(day)
Calculate The density of Freon CF2Cl3 at 30 C and 0.954
Pheromones are compounds secreted by females of manyinsect species to attract mates. Typically, 1.0 × 10−8gof a pheromone is sufficient to reach all targeted maleswithin a radius of 0.50 mi. Calculate the density of thepheromone (in grams per liter) in a cylindrical air spacehaving a radius of 0.50 mi and a height of 40 ft (volumeof a cylinder of radius r and height h is πr2h).
Given: wt NaOH = 10.0g Density of NaOH= 2.16 g/ml Wt. H2O = 200g Density of H2O= 1g/ml Calculate M
How do youcovert 81.2g into kilograms?
Please answer g please In the table below, use your most important scientific instrument (your calculator) to fill in the little boxesthat are highlighted:2. Data TableIdentity of Dehydrated salt (for afterwards) ________________________________ Mass of empty dish 70.874g Mass of dish + hydrated salt 71.346g Mass of hydrated salt Mass of dish + dehydrated salt XXXXXXX a) first heating 71.194g b) second heating 71.174g Mass of dehydrated salt Mass of water lost Wt. % of water in hydrated salt Moles of dehydrated salt Moles of water driven off Empirical formula of hydrated salt a. Show the calculation for obtaining the mass of your hydrated salt used.b. Show the calculation for obtaining the mass of your dehydrated salt after the second heating.c. Show the calculation for obtaining the mass of water that was driven off (based on secondheating).d. Show the calculation for obtaining the weight percent of water that was in your hydrated…
Given the following data forMass of test tube, beaker and cyclohexane = 100.17 gMass of test tube and beaker = 84.07 gFreezing point of cyclohexane = 6.59 oCMass of weighing paper + naphthalene =1.080 gMass of weighing paper = 0.928 gFreezing point solution = 5.11oCKf = 20.8oC/mDetermine the followinga. mass of cyclohexane in g (2 decimal places); _____b. mass of naphthalene in g (4 decimal places); _____c. freezing point depression (2 decimal places); _____d. molality of solution (3 significant figures); _____e. moles of naphthalene (3 significant figures); _____f. molar mass of naphthalene, experimentally (3 significant figures); _____g. % error if theoretical molar mass of naphthalene is 128.17 g/ mole, USE ABSOLUTE VALUE (3 significant figure); ____
Given the following data for Mass of test tube and stearic acid = 14.17 gMass of test tube = 11.40 gFreezing point of strearic acid = 69.59o CMass of weighing paper + naphthalene =1.230 gMass of weighing paper = 0.920 gFreezing point solution = 64.00o CKf = 4.5o C/m Determine the following1. mass of stearic acid in g (2 decimal places); 2.77g2. mass of naphthalene in g (2 decimal places); 0.31g3. freezing point depression (2 decimal places); 3.93oC4. molality of solution (3 significant figures); _____5. moles of naphthalene (3 significant figures); _____6. molar mass of naphthalene, experimentally (3 significant figures); _____7. % error if theoretical molar mass of naphthalene is 128.17 g/ mole, USE ABSOLUTE VALUE (3 significant figure); _____
The U.S. proven natural gas reserves in 2013 were 323 trillion ft3 . How long will these reserves last if there are no imports or exports and if the U.S. annual rate of use of 24.5 trillion ft3 continues?