lim 2 0 1 3.

Q: lim x→−2 (3x^4+2x^2−x+9)

A:

Q: lim 4. 3- a2 - 6r + 9 5. lim 3+ a2 - 6r + 9 6. lim 3 a2-6x + 9

A:

Q: 3. lim 7-t -2 七や3 4-t~1 ゼ

A: We have to find the limit of the given function: limt→37-t-24-t-1+6t Since this is 00 indeterminate…

Q: Find the limits

A:

Q: 3) lim (x² + y²)' 1.

A: Given: limx→0y→0x2+y2x

Q: х2-2х-3 6. lim х-з х2-4х+3

A:

Q: Find the limit.

A: To find: limx→3x+1-2x-3

Q: Find the limit.

A:

Q: limx 3 Vx+2 – V5 x-3

A: Given,              limx→3x+2-5x-3

Q: x-4 3. lim I+4 4 VI - 2

A: We need to evaluate the limit of the given function

Q: lim (1.)(0,0) r +y – a²y²"

A:

Q: lim 5(2x – 1)

A: Here we have to evaluate the limit at x=0 for the given function f(x) = 5(2x-1)

Q: Lim 5x−3 – 4 x→∞ 2x-2 + 9

A: Given,          limx→∞5x-3-42x-2+9

Q: (ii) Limx→∞ ((x − 3)^2)/(x^2/2)− 2x − 3

A:

Q: 1 – 5z2 + 5 lim 1 + 5z3 Answer:

A: Given query is to find the value of the limit.

Q: I+3 lim z-3 + x- 6

A:

Q: х3+9х2+20х 4. lim х-3+ х2+x-12

A:

Q: Lim   ( ((2x − 1)^0/5) − 3)/ x-5 x→5

A:

Q: х —2 Га) lim x4-X-4 x- 3 (b) lim х+2 (х — 2)2

A:

Q: 3. +3 lim %3D

A: Given : limt→03t+3-1t

Q: 23. lim 3x-2 2+ 3

A:

Q: Find the limit

A:

Q: у3-у2-у-2 10. lim у-2 2у3-5у2+5у-6

A: Given: L=limy→2y3-y2-y-22y3-5y2+5y-6 For evaluating given limit, we use L hospital's rule According…

Q: Find the limit L.

A: limx→-2 4x+5

Q: lim (x²+2) sech(x) X → 00

A:

Q: 24. lim 4- 2x x-2

A:

Q: (а) 5x-3 – 4 (i) Lim x-00 2x-2 + 9 (х — 3)2 (ii) Lim X→∞ X2 2 7- 2x – 3 2х —

A: That's easy. Have a great day!!!

Q: lim 2"+1+3"+1 2n +3"

A:

Q: Find the limits

A: lims->2/3(8-3s)(2s-1)

Q: (а) 5x-3 – 4 (i) Lim x-00 2x-2 +9 (х — 3)2 (ii) Lim x-00 x2 7- 2x – 3 2

A:

Q: Lim TE -2 V-4 シラ4

A:

Q: Vミ-2 lim ミー→4 -4

A: Let, L=limz→ 4z-2z-4Rationalize Numerator L=limz→ 4z-2z-4z+2z+2 L=limz→ 4z-4(z-4)(z+2)L=limz→…

Q: X2 4 3) lim メーや2 3-Jx2ょ5 it

A: We will find the solution of this problem.  Here,  we will use L.HOSPITAL. RULE.

Q: lim 2 + 9x° (1 + x ) ( 3 + x* )

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: Lim 5X-1 - 3 J5メ-1 2. メ→2 8-2X

A: use L'Hospital rule to solve given problem...

Q: lim (x + 5)(2x + 5) 1) (x – 2) (b) x → * (3x + ·

A:

Q: (x2-5х -9 20. lim 2x4+3x А. 2 В. О С. о D. -00

A: Let L is the value of given Limit.

Q:

A:

Q: (2х — у — 2 lim (ху) -(2,0) 2х —у —4

A: Multiply by 2x-y+2 in numerator and denominator-…

Q: 3X бх+2—2е lim х 30 5х2—2х3

A:

Q: 3 + 2* is 5* 28. lim 4 X -0 2 (A) 5 (B) 0 (C) (D) nonexistent -- 3/4

A: topic - limits

Q: x1メーコ| 7) tim メ3 x2-9 2\ 8) lim 2X- X-15 メマ メ)x-3|

A: 1. limx→3-xx-3x2-9 x-3=-x+3 as x→3- and x2-9=(x+3)(x-3)…

Q: х — 3 33. lim x→2+ X – 2

A: we have to find the limit of the following

Q: (а) 5x-3 – 4 (i) Lim X-0 2x-2 + 9 (х — 3)2 (ii) Lim 7- 2x -3 2х — 3

A: to solve the limit proceed as follows…

Q: (i) Limx→∞ 5x−3 − 4 / 2x−2 + 9 (ii) Limx→∞ (x − 3)2 / x2/2 − 2x − 3

A: We have to solve given problems:

Q: Find each limit, if it exists.

A: (a) limx→∞ 3-2x3x3-1=limx→∞ x3x-2x3x2-1x=limx→∞ 3x-23x2-1x=0-2∞-0=0 Thus, limx→∞ 3-2x3x3-1=0.

Q: sec (2)7** b) lim ес x→+

A: We have to find limit

Q: x2 - 4 a. limz-1 3r² + 6 c. lim→2 x² – 9 V2x – I – 3 b. limz→-3 d. lim, 45+ 1² + 2x – 3 I- 5

A: We have to find the given limit. (a). limx→1 x2-43x2+6

Q: lim 2 x→2 x²-4 11 11

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.