lim as x goes to infinity of (square root 2x^2+3x-1)/(7x+1). Note: only put the square root on the numerator.

Q: Find the limit of limx->-1 (x3-2x2+5)

A: Since this is a polynomial function,we can calculate the limit by direct substitution. We have The…

Q: 2-limx-o(x. secx.cscx)

A: To find the limit of the following.                                     limx→0 (x sec x csc x)

Q: Calculate limit of (square root of x^3-1)-x^2 as x approach to positive infinity. Thank you!

A:

Q: 7-8e2x lim x→→∞ 12e²x+28

A: To find the limit.

Q: Show that lim(5x+2)=-18 x-> -4

A:

Q: 4-x lim,.

A: The given limit is limx→∞4-xx

Q: find lim ( 3x2 -2x -1) X --> -1

A:

Q: lim(1 + 3x)²/x x→0

A: Concept if limx→0f(x) = 1    and limx→∞g(x) = ∞ then the limx→0f(x)g(x)  = elimx→0[f(x) -1][g(x)]…

Q: What is the lim of squared root x^2-4, if x ---> 2 ^+

A:

Q: Vx +1-1 2. lim

A: we have to find limit

Q: show that : Limx→0    1/ (x – 1) + 1/( x + 1)  ) /x = −2

A: apply the concept of limit to prove the given problem.

Q: lue of lim X→-4 2x+8 x²+2x-8* Remember to fully justify your.

A:

Q: V5x+4-2 -lim

A: Given that : lim(x tends to 0) (√(5x+4)-2/x). We find the value of this limit problem. Here i…

Q: х2-х-2 с. lim х>-1 х3-2x2—3х

A: (c) Given limit is : limx→-1x2-x-2x3-2x2-3x To determine the value of given limit.

Q: 4 - VE lim x>16 16x – x?

A: Given: limx→164-x16x-x2

Q: 4x + x-1 lim 3x- x²

A: Here we have to find limit of the given function.

Q: Use a tble of functional values to evaluate: lim 2²–1| x-1

A: Given, We will calculate the value at some points and then will calculate the limit of given…

Q: Evaluate: " 3x3-3х2-18х lim xsinx+2 sinx

A: Value=?

Q: 5- V4 +3x (3) lim ズ→7 7- x

A: The given function is limx→75-4+3x7-x

Q: limx-->3 x2−x−6/x-3

A:

Q: b. lim -4 In x tan(4x)]

A: Solution:

Q: 1) lim (2x² + x + 4) x--1

A: Given limit, limx→-12x2+x+4

Q: 1- x - x2 lim 2x – 3 x--00

A:

Q: Find: lim --9 ,2_9x x2-9x x→9

A: We have to find value of  Limit x tends to 9  (x-9)/(x^2-9x)

Q: ■ Find the limit.

A: Given- limx→12-xx-12 To find- The value of the above limit.

Q: 32x4-5x+11 lim x-∞0 4x3-12x4

A:

Q: Limit as x approaches 2 of (x3-8)/(x-2)

A: Obtain the value of the limit as follows.

Q: limit as x approaches infinity, -2x^3-2x+3/3x^3+3x^2-5x

A: Here an expression in x is given and we need to find its value when x tends to infinity shown below.

Q: x³ - 125 lim x-5 x - 5

A:

Q: How to find  lim 4-x/x+3 while its approaching 3 from the left side.

A: we have to find limit value as x approaches to 3 from left side.

Q: 35. Lim x2-1 X1 X-1

A: Given,             limx→1x2-1x-1

Q: b. Find lim (xvx²+1-x²)

A: Here, we take common x.then multiply denominator and numerator by √(x^2+1)+x

Q: In x 35. lim

A:

Q: 2x-√5+4x lim x→6 x-3

A: The given limit is limx→62x-5+4xx-3

Q: To determine To find: The value of lim ( - →5 12-41-5 6(1-5)

A:

Q: . Find limx→0 x 3 + 2x − 4/x+1

A: The given limit is

Q: lim (x2 + 2)sechx

A:

Q: Determine limx→−2 6/x-2, if it exists

A: limx→−2 6/x-2 yes limit exist and we can direct apply the limit so put -2 in given function…

Q: 6. Find lim Vx -4 Vx - x>16 x– 16

A:

Q: Find lim as x-->0 (1/x((1+x)^1/3)) - 1/x

A: Refer to the question, we have to find the limit of the provided function (1/x((1+x)^1/3)) - 1/x…

Q: Evaluate lim as x approaches positive infinity (square root of x^2 +7x +5 (end of square root) minus…

A: limx→∞x2=x limx→∞1/x=0 as x is very big number

Q: في Lim X-1 X1 X²-1

A: Hint : Factorise denominator

Q: Lim (112²x - 21²) (sin²x x-0

A: I am attaching image so that you understand each and every step.

Q: Find the limits

A:

Q: If sqrt(5 - 2x2) <=ƒ(x)<= sqrt(5 - x20 for -1<= x<=1, find lim x-->0 ƒ(x)

A:

Q: 8. find limx>2 x-2

A: We have to find the value of limit

Q: ¤ – z² lim +1 1- ya

A: Here we find limx→1x-x21-x.

Q: f(x)= 4x^2 - 14x -8 / x^2 + 4x, if x /= -4 2x-1, if x= -4 Find lim x -> -4 ^ - and  F(-4)

A: The given piecewise function is,

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.