# lim f(x) as x --> 0 for (5 + 2x + sinx)/(6cosx). I did substitution but I don't understand why they have sinx = sin(0) they have that as 1. what is the logic there because x = 0 so wouldn't y be 1 or -1? same goes for cosx = cos(0) when x = 0 y 1 or -1? what am I missing here?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.5: Product-to-sum And Sum-to-product Formulas
Problem 7E
Question

lim f(x) as x --> 0 for (5 + 2x + sinx)/(6cosx). I did substitution but I don't understand why they have sinx = sin(0) they have that as 1. what is the logic there because x = 0 so wouldn't y be 1 or -1? same goes for cosx = cos(0) when x = 0 y 1 or -1? what am I missing here?

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