Lim X-8 メ→2 X-16

Q: 2 lim X + 50 Evaluate X → 00 + 3x + 2 *

A:

Q: Lim [ 3x-2 ]+x

A: We have to find the left hand limit of given function.

Q: lim x→−2 (3x^4+2x^2−x+9)

A:

Q: lim 4. 3- a2 - 6r + 9 5. lim 3+ a2 - 6r + 9 6. lim 3 a2-6x + 9

A:

Q: 3. lim 7-t -2 七や3 4-t~1 ゼ

A: We have to find the limit of the given function: limt→37-t-24-t-1+6t Since this is 00 indeterminate…

Q: х — 3 lim Nx- 3 x→3

A: the given limit is: limx→3x-3x-3 we have to find the value of the given limit.

Q: x² – 4 - lim 3 x→-2 x + 8 O 2/3 О 13 О 13

A:

Q: 4ー Lim X メ→2 x-4

A: Our Aim is to evaluate the limit in the expression given below:-limx→2 x3-8x2-4-(i)

Q: Lim 5x−3 – 4 x→∞ 2x-2 + 9

A: Given,          limx→∞5x-3-42x-2+9

Q: x² – 21x + 54 - lim x → 3 х — 3 - II

A: x2-21x+54=x2-18x-3x+54=x(x-18)-3(x-18)=(x-18)(x-3)

Q: lim z2= 10 20 -2 0 -10

A: The objective is to find the limz→iz2. Since z2 is continuous.

Q: lim x→2 x² – 4

A: Note: Since you have asked multiple question, we will solve the first question for you. If you want…

Q: b) lim x-13 X-0

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Q: Lim メー→& 5X 2X+XSin3 X -2X++

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Q: 5. lim X-0 e2x-1

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Q: Find each limit, if it exists.

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Q: lim 4 8. t. xマ-2 X +2 x* +2x

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Q: lim x2 + 4x + 3 X→-1 1 2.

A: Fro the given problem: limx→-1x2+4x+3

Q: lim x+0 v25 + 8x – 5

A:

Q: lim X+X -4 6x²-5

A: Infinity Limits

Q: Find the limit L.

A: limx→-2 4x+5

Q: х — 6 lim 2 X→ -0 x² + 5

A:

Q: lim (x²+2) sech(x) X → 00

A:

Q: lim 7x+x² X-3

A: Given that, limx→37x+x2x-3

Q: lim V8+X -2

A:

Q: limy 2 X- 2

A: Here we have to evaluate limx→21x-12x-2

Q: lim 3-V5+x 24 X-4

A: This is one of the simplest topics of algebra i.e. limits and this question can be done with just…

Q: Find the limit L.

A: To find: The limit of limx→-4x2+4x. Calculation: The limit of limx→-4x2+4x can be obtained as,…

Q: lim (Vx - 1) 4 X. x→27

A:

Q: lim (2e3x+5)

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Q: lim (x2 – x')e?* X -

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Q: lim 3X + x?+2 X-> X+ -2 2X +X2 V 3h +4 -2 lin!

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Q: lim (lnx/x1/2 - 1/x)  ? x-->infinity

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Q: Lim 7X + X メー3 メ > 3

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Q: ® Lim V3X mm 3 X-→3 X ¢3 X- 3

A:

Q: lim (x-7x – 2x+5) is infinity. |

A: Topic = Limits

Q: lim (x²+2x-3) x-4

A: Solution Givenlimx→4(x2+2x-3)we need to find the limit approach

Q: 3 (c) lim 6.x x-3 r2 – 9

A:

Q: X2 4 3) lim メーや2 3-Jx2ょ5 it

A: We will find the solution of this problem.  Here,  we will use L.HOSPITAL. RULE.

Q: lim e5x — 2e-2х + е-3х + 2е-5х —5е-10х n→0∞ 2х-4

A: Topic:- limits

Q: lim 3) x700 9e x/5

A:

Q: lim (x + 5)(2x + 5) 1) (x – 2) (b) x → * (3x + ·

A:

Q: lim 7x + 3. x-2

A:

Q: Lim Nx-2 X→2_×<ー4

A: Solution-

Q: lim 4x45 X-D5 X+5

A: Given, limx→5 4x+5x+5

Q: Lim メ、+x-2 -『 メ -→1 2ナ+ メャ2

A:

Q: 4. lim (x- 5x- 2x – x² + 100)

A:

Q: 3) lim (x- 3x + 4) 4) lim -V2x-2 A) -5 C) 0 B) 2 D) 7 A) V12 C) 2 B) -7 D) -6

A: 3.

Q: lim x→n x²_n² x-n = 10

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.