Limiting and Excess Reagent  1. In the production of Zinc sulfide, 36.8 g of zinc is made to react with 19.4 g of sulfur. Zn+S = ZnS a. How many moles of ZnS is produced when sulfur is completely used up? b. How many grams of ZnS is produced when zinc is completely used up? c. Which reactant is the limiting reagent?

Chemistry: Matter and Change
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Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
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Chapter11: Stoichiometry
Section: Chapter Questions
Problem 75A
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Limiting and Excess Reagent 

1. In the production of Zinc sulfide, 36.8 g of zinc is made to react with 19.4 g of sulfur. Zn+S = ZnS

a. How many moles of ZnS is produced when sulfur is completely used up?

b. How many grams of ZnS is produced when zinc is completely used up?

c. Which reactant is the limiting reagent?

d. How many grams of the excess reagent is left? 

1. h the production of Zinc sulfide, 36.8 g of zinc is made to react with 19.4 g of sulfur.
Zn +S - Zns
a. How many moles of ZnS is produced when sulfur is completely used up?
b. How many grams of ZnS is produced when zinc is completely used up?
c. Which reactant is the limiting reagent?
d. How many grams of the excess reagent is left?
2. An aqueous solution of NaOH candissolve an aluminum sheet in the reaction:
2 Al + 2 NaOH + 2H20 -2 NAAIO2 + 3 H2
If 126.4 g of NaOH is 97.7 g of Al are made to react,
a. How many moles of NAAIO, is produced if 126.4 g of NaOH reads completely?
b. How many grams of NAAIO2 is produced using the same amount of NaOH?
c. Which reactant is the limiting reagent?
d. How many grams of the excess reagent is left?
Transcribed Image Text:1. h the production of Zinc sulfide, 36.8 g of zinc is made to react with 19.4 g of sulfur. Zn +S - Zns a. How many moles of ZnS is produced when sulfur is completely used up? b. How many grams of ZnS is produced when zinc is completely used up? c. Which reactant is the limiting reagent? d. How many grams of the excess reagent is left? 2. An aqueous solution of NaOH candissolve an aluminum sheet in the reaction: 2 Al + 2 NaOH + 2H20 -2 NAAIO2 + 3 H2 If 126.4 g of NaOH is 97.7 g of Al are made to react, a. How many moles of NAAIO, is produced if 126.4 g of NaOH reads completely? b. How many grams of NAAIO2 is produced using the same amount of NaOH? c. Which reactant is the limiting reagent? d. How many grams of the excess reagent is left?
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