Limiting Reagent Investigation Introduction: In this lab a precipitate will be formed by mixing solutions of sodium carbonate and lead II nitrate. The solutions will be mixed in test tubes of uniform size, so that the amounts of precipitate produced can be compared by measuring the heights of the solids in the test tubes. You and a partner will be working with two other groups (total of 6 students). Each group will be responsible for two of the test tubes (A & B, C & D, E & F). Organize yourselves accordingly. You will only be dispensed 40 mL of each solution. Pre-lab: Write a balanced chemical equation (BCE) for this reaction (include states) Materials: ● 40 mL of 0.75 mol/L Two pipettes with pumps sodium carbonate solution ● 6 test tubes ● Test tube rack • 40 mL of 0.75 mol/L lead Il nitrate solution ● Ruler . Two labeled beakers Procedure: 1. Obtain 40 mL of each reactant from the front of the classroom. 2. Label 6 identical sized test tubes A-F. Check that diameters are equal. 3. Add the volume indicated on the data table using two separate pipettes to deliver appropriate volumes of each reactant to each test tube. Note: add the larger volume of solution second to ensure efficient mixing. 4. Gently mix the contents of each test tube without letting too much precipitate stick to the sides of the test tube. 5. Once the reagents have been mixed allow the solid precipitates to settle for about 3-5 minutes. Tap the tubes gently so the precipitate settles evenly (flat surface on top). 6. After the precipitate in each five test tubes has settled, use a metric ruler measure the height in mm of solid in each test tube. Record the height of each precipitate in the data table. Observations: Table 1.0: Height of precipitate obtained with variable lead II nitrate volumes at constant sodium carbonate volume Volume of sodium Volume of carbonate Lead Il nitrate 4.0 mL 1.0 mL 4.0 ml. 3.0 ml. 4.0 mL 5.0 mL 4.0 mL 7.0 mL 4.0 mL 9.0 mL 4.0 mL 11.0 mL Test tube A B C D E F Height of precipitate in mm
Limiting Reagent Investigation Introduction: In this lab a precipitate will be formed by mixing solutions of sodium carbonate and lead II nitrate. The solutions will be mixed in test tubes of uniform size, so that the amounts of precipitate produced can be compared by measuring the heights of the solids in the test tubes. You and a partner will be working with two other groups (total of 6 students). Each group will be responsible for two of the test tubes (A & B, C & D, E & F). Organize yourselves accordingly. You will only be dispensed 40 mL of each solution. Pre-lab: Write a balanced chemical equation (BCE) for this reaction (include states) Materials: ● 40 mL of 0.75 mol/L Two pipettes with pumps sodium carbonate solution ● 6 test tubes ● Test tube rack • 40 mL of 0.75 mol/L lead Il nitrate solution ● Ruler . Two labeled beakers Procedure: 1. Obtain 40 mL of each reactant from the front of the classroom. 2. Label 6 identical sized test tubes A-F. Check that diameters are equal. 3. Add the volume indicated on the data table using two separate pipettes to deliver appropriate volumes of each reactant to each test tube. Note: add the larger volume of solution second to ensure efficient mixing. 4. Gently mix the contents of each test tube without letting too much precipitate stick to the sides of the test tube. 5. Once the reagents have been mixed allow the solid precipitates to settle for about 3-5 minutes. Tap the tubes gently so the precipitate settles evenly (flat surface on top). 6. After the precipitate in each five test tubes has settled, use a metric ruler measure the height in mm of solid in each test tube. Record the height of each precipitate in the data table. Observations: Table 1.0: Height of precipitate obtained with variable lead II nitrate volumes at constant sodium carbonate volume Volume of sodium Volume of carbonate Lead Il nitrate 4.0 mL 1.0 mL 4.0 ml. 3.0 ml. 4.0 mL 5.0 mL 4.0 mL 7.0 mL 4.0 mL 9.0 mL 4.0 mL 11.0 mL Test tube A B C D E F Height of precipitate in mm
Chapter3: Statistical Tests With Excel
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Transcribed Image Text:Limiting ReagEnt Investigation
Introduction: In this lab a precipitate will be formed by mixing solutions of sodium carbonate and lead II
nitrate. The solutions will be mixed in test tubes af uniform size, so that the amounts of precipitate produced can be
compared by measuring the heights of the solids in the test tubes. You and a partner wiln be working with two
other groups (tatal of 6 students). Each group will be responsible for two of the test tubes (A & B, C& D, E & F).
Organize yourselves accordingly Yau will only be dispensed 40 mL of each solution.
Pre- lab: Write a balanced chemical equation (BCE) for this reaction (include states)
Materials:
40 mL of 0.75 mol/L
• Two pipettes with pumps
6 test tubes
sodium carbonate solution
40 mL of 0.75 mol/L lead IIl nitrate
Test tube rack
solution
Ruler
• Two labeled beakers
Procedure:
1. Obtain 40 mL of each reactant from the front of the classroom.
2. Label 6 identical sized test tubes A-F. Check that diameters are equal.
3. Add the volume indicated on the data table using two separate pipettes to deliver
appropriate volumes of each reactant to each test tube. Note: add the larger
volume of solution second to ensure efficient mixing.
4. Gently mix the contents of each test tube without letting too much precipitate stick
to the sides of the test tube.
5. Once the reagents have been mixed allow the solid precipitates to settle for about
3-5 minutes. Tap the tubes gently so the precipitate settles evenly (flat surface on
top).
6. After the precipitate in each five test tubes has settled, use a metric ruler measure
the height in mm of solid in each test tube. Record the height of each precipitate in
the data table.
Observations:
Table 1.0:
Height of precipitate obtained with variable lead II nitrate
volumes at constant sodium carbonate volume
Volume of
Height of
precipitate in mm
Test tube
Volume of sodium
carbonate
Lead II nitrate
1.0 ml.
3.0 mL
5.0 ml.
4.0 mL
B
4.0 ml.
4.0 mL
4.0 mL
7.0 mL
4.0 mL
9.0 mL
F
4.0 mL
11.0 mL
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