lina obtains a z-score of -1.16 from her study that has an alpha level of .05. Which of the following must be true? A. If she has a directional hypothesis, she will be able to reject the null hypothesis. B. If she has a non-directional hypothesis, she will be able to reject the null hypothesis. C. Her obtained z-score is not within the rejection region. D. Not enough information provided
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- Repeat Example 5 when microphone A receives the sound 4 seconds before microphone B.If after performing a t-test for comparison of means (alpha= .05) we obtain p=0.0256, what is our conclusion? a. Fail to reject H0 b. Reject H0 c. Reject H1 d. Unable to determine from the information providedIf the critical t is ±1.796 and the obtained t is -2.09, what decision would you make regarding the null hypothesis?
- The article in the ASCE Journal of Energy Engineering (1999, Vol. 125, pp.59-75) describes a study of the thermal inertia properties of autoclaved aerated concrete used as a building material. Five samples of the material were tested in a structure, and the average interior temperatures (°C) reported were as follows: 23.01, 22.22, 22.04, 22.62, and 22.59. Test that the average interior temperature is equal to 22.5°C using alpha (a) = 0.05. This problem is a test on what population parameter? What is the null and alternative hypothesis? What are the Significance level and type of test? What standardized test statistic will be used? What is the standard test statistic? What is the Statistical Decision? What is the statistical decision in the statement form?If the value of Cronbach’s alpha is 0.07, it means ___________; a. Research instrument is not reliable b. Research instrument is internally consistent c. Data is reliable d. Data is internally consistentSolve An article in the ASCE Journal of Energy Engineering (1999, Vol. 125, pp.59-75) describes a study of the thermal inertia properties of autoclaved aerated concrete used as a building material. Five samples of the material were tested in a structure, and the average interior temperatures (°C) reported were as follows: 23.01, 22.22, 22.04, 22.62, and 22.59. Test that the average interior temperature is equal to 22.5°C using alpha (a) = 0.05. 1.)This problem is a test on what population parameter? a.Variance/ Standard Deviation b.Mean c.Population Proportion d.None of the above 2.)What is the null and alternative 3 points hypothesis? a.Ho / (theta = 22.5) , Ha: (0 # 22.5) b.Ho / (theta > 22.5) , Ha: (0 # 22.5) c.Ho / (theta < 22.5) , Ha: (theta >= 22.5) d.None of the above 3.)What are the Significance level 3 points and type of test? alpha = 0.05 two-tailed alpha = 0.95 two-tailed alpha = 0.95 one-tailed None of the above 4.)What standardized test statistic will…
- Qa) attached below Qb) attached below Qc) ? (alpha) = ? Qd) ? (beta) = ?Let X1, . . . , Xn ∼ iid Unif(θ1, θ2), where both θ1 and θ2 are unknown. Find the MOM estimator and compare them to the MLE.Consider the following null and alternative hypotheses for testing whether the average GPA of university students is different than 3.2. H0:u = 3.2 Ha:u not= 3.2 In this case, the consequence of Type I error is... a. assuming university students have a GPA equal to 3.2, when in fact it is not equal to 3.2. b. assuming university students have a lower GPA than 3.2, when in fact it is equal to 3.2. c. assuming university students have a higher GPA than 3.2, when in fact it is equal to 3.2. d. assuming university students have a GPA not equal to 3.2, when in fact it is equal to 3.2.
- You conduct a hypothesis test and find that your data are statistically significant at alpha = 0.03. What may you conclude? A. The data would also be significant at alpha = 0.02. B. The data would also be significant at alpha = 0.05. C. Both A and B are true. D. Neither A nor B is true.A company specializes in producing bunkers located in places with extremely cold climates under 0°C. A prototype for a new bunker design using different structure design and materials was tested to have the following average interior temperatures: 23.01, 22.22, 22.04, 22.62, and 22.59. Test that the average interior temperature is equal to 22.5 °C using α = 0.05. a.What are the hypothesis statements?using the z table (table e), find the critical value (or values) for each. a. alpha=0.10, two tailed test b. alpha=0.01, right tailed test c. aplha=0.005, left tailed test