Asked Dec 25, 2019

Liquid helium has a very low boiling point, 4.2 K, as well as a very low latent heat of vaporization, 2.00 x 104 J/kg. If energy is transferred to a container of liquid helium at the boiling point from an immersed electric heater at a rate of 10.0 W, how long does it take to boil away 2.00 kg of the liquid?


Expert Answer

Step 1

Amount of heat requir...


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Q = mL m → mass of li quid=2kg L→ Latent heat of vapourization = 2×10ʻJ/kg Q = (2kg) (2x10* J/kg) = 4x10* J


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