# Liquid octane(CH3(CH2)6CH3)will react with gaseous oxygenO2to produce gaseous carbon dioxideCO2and gaseous waterH2O. Suppose 8.00 gof octane is mixed with 18. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Question
Asked Sep 29, 2019
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Liquid octane

(CH3(CH2)6CH3)

will react with gaseous oxygen

O2

to produce gaseous carbon dioxide

CO2

and gaseous water

H2O

. Suppose 8.00 gof octane is mixed with 18. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

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Step 1

The balanced reaction between octane and oxygen is written below.

2C8H18+25O2 → 16CO2+18H2O

The mass, 228.46 g of octane reacts with 800 g of oxygen. Thus, the amount of oxygen required by 8.0 g of octane is calculated in equation (1).

Thus, 8.0 g of octane requires 28.01 g of oxygen. The given amount of oxygen is  18.0 g . Therefore, oxygen is present in excess and the limiting reagent is octane.

Step 2

According to the balanced reaction, 228.46 g of octane reacts with 704 g of carbon dioxide.

The ...

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