liseconds. Assume an ACK is small enough that you can ignore its transmission delay. You may also assume that no packets are lost, damaged, or reordered. For this question, a reliable data transfer is considered finished when all ACKs have been received by the sender.
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Consider a sender using a reliable data transfer protocol. The sender wants to send 9 packets to a receiver. The transmission delay for a single packet is 40 milliseconds. The propagation delay between the hosts is 100 milliseconds.
Assume an ACK is small enough that you can ignore its transmission delay. You may also assume that no packets are lost, damaged, or reordered.
For this question, a reliable data transfer is considered finished when all ACKs have been received by the sender.
How long would this take using a pipelined reliable data transfer protocol with a window size of 6?
In milliseconds
How long would this take using a non-pipelined reliable data transfer protocol?
In milliseconds
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Solved in 2 steps
- Consider two hosts, A and B, connected by a single link of rate R bps. Suppose that the two hostsare separated by m meters, and suppose the propagation speed along the link is s meters/sec.Host A is to send a packet of size L bits to host B.a. Express the propagation delay, dprop, in terms of m and s.b. Determine the transmission time of the packet, dtrans, in terms of L and R.c. Ignoring processing and queuing delays, obtain an expression for the end-to-end delay.d. Suppose host A begins to transmit the packet at time t= 0, at time t =dtrans, where is the lastbit of the packet?e. Suppose dprop is greater than dtrans. At time t =dtrans, where is the first bit of the packet?Consider the GBN protocol with a sender window size of 4 and a sequence number rangeof 1,024. Suppose that at time t, the next in-order packet that the receiver is expecting has asequence number of k. Assume that the medium does not reorder messages. Answer thefollowing questions: What are all possible values of the ACK field in all possible messages currently propagating back to the sender at time t? Justify your answer.Consider a packet of length L that begins at end system A and travels over three links to a destination end system. These three links are connected by two packet switches. Let di, si, and Ri denote the length, propagation speed, and the transmission rate of link i, for i=1,2,3. The packet switch delays each packet by dproc. Assuming no queuing delays, in terms of di, si, Ri, (i=1,2,3), and L, what is the total end-to-end delay for the packet? Suppose now the packet is 1,200 bytes, the propagation speed on all three links is 2.5x10^8 m/s, the transmission rates of all three links are 2 Mbps, the packet switch processing delay is 3 msec, the length of the first link is 4,000 km, the length of the second link is 3,000 km, and the length of the last link is 1,500 km. For these values, what is the end-to-end delay? In the above problem, suppose R1=R2=R3=R and dproc=0. Further suppose the packet switch does not store-and-forward packets but instead immediately transmits each bit it receives…
- Consider a packet of length L that begins at end system A and travels over three links to a destination end system. These three links are connected by two packet switches. Let d, s , and R denote the length, propagation speed, and the transmission rate of link i, for i=1,2,3 . The packet switch delays each packet by d . Assuming no queuing delays, in terms of d, s , R, , and L, what is the total end-to-end delay for the packet? Suppose now the packet is 1,500 bytes, the propagation speed on all three links is 2.5⋅108m/s the transmission rates of all three links are 2 Mbps, the packet switch processing delay is 3 msec, the length of the first link is 5,000 km, the length of the second link is 4,000 km, and the length of the last link is 1,000 km. For these values, what is the end-to-end delay?Consider a packet of length L which begins at end system A and travels over three links to a destination end system. These three links are connected by two packet switches. Let di, si, and Ri denote the length, propagation speed, and the transmission rate of link i, for i = 1, 2, 3. The packet switch delays each packet by dproc. Assuming no queuing delays, in terms of di, si, Ri, (i = 1,2,3), and L, what is the total end-to-end delay for the packet? Suppose now the packet is 1,500 bytes, the propagation speed on all three links is 2.5*108 m/s, the transmission rates of all three links are 2 Mbps, the packet switch processing delay is 3 msec, the length of the first link is 5,000 km, the length of the second link is 4,000 km, and the length of the last link is 3,000 km. For these values, what is the end-to-end delay?Consider two hosts, A and B, connected by a single link of rate R bps. Suppose that the two hosts are separated by m meters, and suppose the propagation speed along the link is s meters/sec.Host A is to send a packet of size L bits to host B.a. Express the propagation delay, dprop, in terms of m and s.b. Determine the transmission time of the packet, dtrans, in terms of L and R.c. Ignoring processing and queuing delays, obtain an expression for the end-to-end delay.d. Suppose host A begins to transmit the packet at time t= 0, at time t =dtrans, where is the last bit of the packet?e. Suppose dprop is greater than dtrans. At time t =dtrans, where is the first bit of the packet?f. Suppose dprop is less than dtrans. At time t =dtrans, where is the first bit of the packet?g. Suppose s = 2.5 x 10^8 , L=100 bits, and R=28 Kbps. Find the distance m so that dprop = dtrans.
- Consider two hosts, A and B, connected by a single link of rate R bps. Suppose that the two hosts are separated by m meters, and suppose the propagation speed along the link is s meters/sec. Host A is to send a packet of size L bits to host B.a. Express the propagation delay, dprop, in terms of m and s.b. Determine the transmission time of the packet, dtrans, in terms of L and R.c. Ignoring processing and queuing delays, obtain an expression for the end-to-end delay.d. Suppose host A begins to transmit the packet at time t= 0, at time t =dtrans, where is the last bit of the packet?e. Suppose dprop is greater than dtrans. At time t =dtrans, where is the first bit of the packet?f. Suppose dprop is less than dtrans. At time t =dtrans, where is the first bit of the packet?g. Suppose s = 2.5 x 108, L=100 bits, and R=28 Kbps. Find the distance m so that dprop = dtrans.Consider a scenario in which Host A wants to simultaneously send packets to Hosts B and C. A is connected to B and C via a broadcast channel—a packet sent by A is carried by the channel to both B and C. Suppose that the broadcast channel connecting A, B, and C can independently lose and corrupt packets (and so, for example, a packet sent from A might be correctly received by B, but not by C). Design a stop-and-wait-like error-control protocol for reliably transferring packets from A to B and C, such that A will not get new data from the upper layer until it knows that both B and C have correctly received the current packet. Give FSM descriptions of A and C.Consider a network with 4 links between two hosts where the maximum allowable packet size is 1000 bits; each link has a transmission rate of 2000 bits per second, except the second link has a transmission rate of 1000 bits per second. How long does it take to send 6000 bits from one host to the other? You may ignore propogation delay, assume there is no other traffic on the network, and assume that no routers drop packets due to queue length. Round your answer to two decimal places.
- Consider two hosts, A and B, connected by a single link of rate R bps. Suppose that the two hosts are separated by m meters, and suppose the propagation speed along the link is s meters/sec. Host A is to send a packet of size L bits to host B. d. Suppose host A begins to transmit the packet at time t= 0, at time t=dtrans, where is the last bit of the packet?e. Suppose dprop is greater than dtrans. At time t =dtrans, where is the first bit of the packet? f. Suppose dprop is less than dtrans. At time t =dtrans, where is the first bit of the packet?g. Suppose s = 2.5 x 108 , L=100 bits, and R=28 Kbps. Find the distance m so that dprop = dtrans.This elementary problem begins to explore propagation delay and transmission delay, two central concepts in data networking. Consider two hosts, A and B, connected by a single link of rate R bps. Suppose that the two hosts are separated by m meters, and suppose the propagation speed along the link is s meters/sec. Host A is to send a packet of size L bits to Host B. a. Express the propagation delay, dprop, in terms of m and s.b. Determine the transmission time of the packet, dtrans, in terms of L and R.c. Ignoring processing and queuing delays, obtain an expression for the end-to-end delay.d. Suppose Host A begins to transmit the packet at time t = 0. At time t = dtrans, where is the last bit of the packet?e. Suppose dprop is greater than dtrans. At time t = dtrans, where is the first bit of the packet?f. Suppose dprop is less than dtrans. At time t = dtrans, where is the first bit of the packet?g. Suppose s = 2.5 * 108 meters/sec, L = 120 bits, and R = 0.112 Mbps. Find the distance m…Consider a packet of length L that begins at end system A and travels over three links to a destination end system. These three links are connected by two packet switches. Let d, s, and R denotes the length, propagation speed, and the transmission rate of link i, for i=1,2,3 . The packet switch delays each packet by d . Assuming no queuing delays, in terms of d, s , R, (i=1,2,3), and L, what is the total end-to-end delay for the packet? Suppose now the packet is 1,500 bytes, the propagation speed on all three links is the transmission rates of all three links are 2 Mbps, the packet switch processing delay is 3 msec, the length of the first link is 5,000 km, the length of the second link is 4,000 km, and the length of the last link is 1,000 km. For these values, what is the end-to-end delay? In the above problem, suppose R1=R2=R3=R and dproc=0. Further, suppose the packet switch does not store-and-forward packets but instead immediately transmits each bit it receives before waiting…