Listed below are the lead concentrations in ug/g measured in different traditional medicines. Use a 0.10 significance level to test the claim that the mean lead concentration for all such medicines is less than 14 µg/g. Assume that the sample issimple random sample.41310.5142.59.51741118.5 OAssuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses?A. Ho: μ= 14 μg/gB. Ho: μ 14 μα/gH: μ> 14 μg/gH1: µ# 14 µg/gO C. H: μ> 14 μg/gD. Ho: H = 14 µg/gH1:µ< 14 µg/gΗ: μ< 14 μg/gDetermine the test statistic.- 2.06 (Round to two decimal places as needed.)Determine the P-value.(Round to three decimal places as needed.)

The random variable lead concentration follows normal distribution. The population mean is 14 ug/g.…

Answered: Listed below are the lead…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Listed below are the lead concentrations in mu g/g measured in different traditional medicines. Use a 0.10 significance level to test the claim that the mean lead concentration for all such medicines is less than 20 mu g/g. Assume that the sample is a simple random sample. 3.5 15.5 16.5 15 13 12.5 21.5 16.5 22.5 16.5 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. Upper H 0 : mu greater than20 mu g/g Upper H 1 : mu less than20 mu g/g B. Upper H 0 : mu equals20 mu g/g Upper H 1 : mu less than20 mu g/g C. Upper H 0 : mu equals20 mu g/g Upper H 1 : mu not equals20 mu g/g D. Upper H 0 : mu equals20 mu g/g Upper H 1 : mu greater than20 mu g/g
Listed below are the lead concentrations in μg/g measured in different traditional medicines. Use a 0.10 significance level to test the claim that the mean lead concentration for all such medicines is less than 16 μg/g. Assume that the sample is a simple random sample. 15.5 18 10 7 4.5 11.5 10 18.5 10 13.5 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0: μ>16 μg/g H1: μ<16 μg/g B. H0: μ=16 μg/g H1: μ>16 μg/g C. H0: μ=16 μg/g H1: μ<16 μg/g D. H0: μ=16 μg/g H1: μ≠16 μg/g Determine the test statistic. nothing (Round to two decimal places as needed.) Identify the range of values for P-value. (You will not enter it here; you will use it to make your decsion below.) State the final conclusion that addresses the original claim. ▼ Reject Fail to reject H0. There…
Listed below are the lead concentrations in mu g/g measured in different traditional medicines. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 21mu g/g. Assume that the sample is a simple random sample. 8 16 17.5 21 22 22 14.5 22.5 12 6.5 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses?
Listed below are the lead concentrations in μg/g measured in different traditional medicines. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 14 μg/g. Assume that the sample is a simple random sample. 3.5 17 13 2.5 10 20 6.5 17 8.5 2.5 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0:μ=14μg/g H1:μ>14μg/g B. H0:μ>14μg/ H1:μ<14μg/g C. H0:μ=14μg/g H1:μ≠14μg/g D. H0:μ=14μg/g H1:μ<14μg/g Determine the test statistic. ______________ (Round to two decimal places as needed.) Determine the P-value. ____________ (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. (1) _____________H0. There is (2) evidence to conclude that the mean lead concentration for all such…
Listed below are the lead concentrations in μg/g measured in different traditional medicines. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 16 μg/g. Assume that the sample is a simple random sample. 12 19 8.5 13.5 17 6.5 4.5 18 17.5 20.5 Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0: μ=16 μg/g H1: μ>16 μg/g B. H0: μ=16 μg/g H1: μ≠16 μg/g C. H0: μ=16 μg/g H1: μ<16 μg/g D. H0: μ>16 μg/g H1: μ<16 μg/g Determine the test statistic. T= ______ (Round to two decimal places as needed.) Determine the P-value. P = _____ (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. (Fail to reject OR Reject) H0. There is (sufficient OR not sufficient)evidence…
Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 34 of the 39 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 98 of the 115 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. Identify the test statistic:Z= ___?____ Identify the P-Value: _______State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. _________Identify the confidence interval limits for the appropriate confidence interval.__?____ < P1-P2 < __?____
Listed below are the lead concentrations in μg/g measured in different traditional medicines. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 17 μg/g. Assume that the sample is a simple random sample. 8 8.5 21 13 18 21.5 11 13 13 21 a) Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? b) Determine the test statistic. c) Determine the eP-value. d) (Reject/fail to reject). There is (sufficient/not sufficient) evidence to conclude that the mean lead concentration for all such medicines is (=, not, >,<) 17.
Given the null and alternative hypotheses, sample means, sample sizes, and population standard deviations shown to the right, conduct a hypothesis test using an alpha level equal to 0.01. h0: u1 - u2 > 0 h1: u1 - u2 < 0 x1= 149 x2 = 139 o1= 17. o2=13 n1=45 n2= 55 Determine the rejection region for the test statistic z. Select the correct choice below and fill in the answer box to complete your choice. (Round to two decimal places as needed.) a z<. or. x> b z> c z< Calculate the value of the test statistic.z = (Round to two decimal places as needed.) Since the test statistic (1) in the rejection region, (2) the null hypothesis. There is (3) (1) is not is evidence to conclude that the mean of population 1 is less than the mean of population 2. 1) is not 2) reject 3) insufficient is do not reject sufficient
Consider the following hypothesis test: h0 = 18 against h1 = 18 A sample of 48 provided a sample mean 17 and a sample standard deviation 4.5. Compute the value of the test statistic. What is the p-value? At , what is your conclusion? What is the rejection rule using the critical value? What is your conclusion?
Use the pulse rates in beats per minute of a random sample of adult females listed in the data set that is available below to test the claim that the means is less than 74 b. p.m. Use a 0.10 significance level.
The National Cyber Security Alliance claims that 85% of computer owners believe that they have a antivirus program installed on their computer. If a random sample of 400 scanned computers found that 324 of them (81%) actually had an antivirus program installed, use the sample proportion to test the claim at the 90% (? = 0.10) significance level. Use the hypothesis H0: p = 0.85 and H1: p ≠ 0.85 with a two-tail test: Compute the Z score for the test statistic = 0.81 (A) ̶ 1.64 (B) ̶ 1.83 (C) ̶ 2.24 (D) ̶ 1.43
Listed below are the heights (in inches) of fathers and their first sons. The dataare from a journal kept by Francis Galton. Use a 0.05 significance level to testthe claim that there is no difference in heights between fathers and their firstsons. (State the null and alternate hypothesis, the p-value method to make adecision, and write a conclusion based on the results.) Height of Father 72.0 66.0 69.0 70.0 70.0 70.0 70.0 75.0 68.265.0Height of Son 73.0 68.0 68.0 71.0 70.0 70.0 71.0 71.0 70.063.0

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