Lysine (K) is a triprotic amino acid whose most protonated form has a charge of 2+. Its acid dissociation constants are pK31 = 1.77, pK32 =9.07, and pkg3 = 10.82.For numbers 1 and 2 refer to the following choices. Write only the letter corresponding to your answer.a. H3K2+ b. H2K²* c. HK2+d. H3K*e. H2K*f. HK*g. H3K h. H2Ki. HK j. H2K-К. НКI. K-m. НК2- п. К2- о. КЗ-1) At pH 7.47, the second most abundant species is2) What is the third most abundant species at this pH?3) At what pH is the concentration of the diprotic species equal to the concentration of the fully deprotonated species. (ANSWER FORMAT:If for example, the answer is 7.12, then c = 7, m =12)C =m =

Groups, whose pKa< given pH get deprotonated and groups, whose pKa> given pH get protonated…

Lysine (K) is a triprotic amino acid whose most protonated form has a charge of 2+. Its acid dissociation constants are pk31 = 1.77, pK2 = 9.07, and pk33 = 10.82. For numbers 1 and 2 refer to the following choices. Write only the letter corresponding to your answer. a. H3K²+ b. H2K²+ c. HK2+ d. H3K* e. H2K* f. HK* g. H3K h. H2K i. HK j. H2K¯ k. HK- I. K- m. HК2- п. К2- о. КЗ- 1) At pH 7.47, the second most abundant species is 2) What is the third most abundant species at this pH? 3) At what pH is the concentration of the diprotic species equal to the concentration of the fully deprotonated species. (ANSWER FORMAT: If for example, the answer is 7.12, then c = 7, m =12) C = m =

Lysine (K) is a triprotic amino acid whose most protonated form has a charge of 2+. Its acid dissociation constants are pk31 = 1.77, pK2 = 9.07, and pk33 = 10.82. For numbers 1 and 2 refer to the following choices. Write only the letter corresponding to your answer. a. H3K²+ b. H2K²+ c. HK2+ d. H3K* e. H2K* f. HK* g. H3K h. H2K i. HK j. H2K¯ k. HK- I. K- m. HК2- п. К2- о. КЗ- 1) At pH 7.47, the second most abundant species is 2) What is the third most abundant species at this pH? 3) At what pH is the concentration of the diprotic species equal to the concentration of the fully deprotonated species. (ANSWER FORMAT: If for example, the answer is 7.12, then c = 7, m =12) C = m =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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