m 9 The maximum current in a superconducting solenoid can be as large as 3.75 kA. ▼ Part A If the number of turns per meter in such a solenoid is 3630 m ¹, what is the magnitude of the magnetic field it produces? View Available Hint(s) IVE| ΑΣΦ B= Submit Provide Feedback ? T
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- The arrangement illustrated in the figure below is composed of six finite straight wires of length l. The electric current flowing in such an arrangement is i. Using the Biot-Savart law, calculate: The magnitude of the magnetic field at point P due to the wire located along segment ab.The answer is in the second image. I am trying to use the standard biot-savart, which is B = (μ0*I/4π) * ∫dl * sinθ / r^2, and it always gives me 16*pi*l at the denominator, instead of 8pi*l. Solve it using B = (μ0*I/4π) * ∫dl * sinθ / r^2, and note that the image with the answer is correct.Instructions1. In the three cases, use the average of the two angles ( = (+) + () =2), the averageof the two currents ( I = I(+) + I() =2), and Eqs. (1) and (2), and calculate coilÖeld and the earth ís horizontal component of magnetic Öeld, B(earth) H [ Tesla ].2. Based on the three previous calculations, what is your experimental determination ofthe horizontal component of the earthís magnetic Öeld, B(earth) H [ Gauss ]?3. Take the accepted value of the earthís horizontal component of magnetic Öeld in southFlorida to be 0:25 Gauss and calculate the percent error in your answer.In the figure below, a uniform magnetic field of 0.5 T points directly into the plane of the paper as shown below. The bottom section acts as a velocity selector, so that the crossed electric field (uniform in the entire region) of strength 2.08X105 V/m and magnetic field allows only positive ions q with a certain velocity to reach the slit S1. After passing through the S1, the singly ionized positive ions experience a magnetic force only (same uniform magnetic field as bottom section), which can separate isotopes with different masses, and only selected mass will reach one of the slits S2 or S3. a. What is the mass of the particles that will reach the second slit, if the distance between the slits are 40 cm (1 and 2 or 1 and 3). b. If the magnetic field is doubled in both regions, while keeping electric field same what is the new mass that will reach the second slit S2/S3.
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- In the upper half space, which is the empty space, I = 7 A current flows from the infinitely long wire along the y axis that intersects the z axis at the point C (0,0,10). Half-space z <0 is from a material with relative magnetic permeability µr = 5. Write numerically the sum of the components (Hx + Hy + Hz) at the point A (-5, -5,0 +) of the magnetic field H [A / m] vector in terms of the given magnitudes (in the half space z> 0).a) Suppose we have an electron moving perpendicular to a B-field along a circular path of radius 18 cm. If imposition of an E-field of 17.1 kV/m makes the path straight, what is the value of B? b) Suppose our E-field measurement has an uncertainty of 0.75 kV/m and our radius of curvature measurement has an uncertainty of 0.2 cm. What is the total uncertainty associated with the magnetic field we just calculated?The average intensity of sunlight reaching Earth is about 1360 W/m2. What is the rms magnetic field of a TEM wave with this intensity? The Earth’s magnetic field has a magnitude of 5 × 10-5 T. How does your answer from part (a) compare? Why don’t we feel this magnetic field?
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