M, a solid cylinder (M=1.51 kg, R=0.123 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.710 kg mass, i.e., F = 6.965 N. Calculate the angular acceleration of the cylinder. Because the bearing is thin, the moment of inertia of the bearing is essentially that of a solid cylinder

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Chapter10: Rotational Motion
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M, a solid cylinder (M=1.51 kg, R=0.123 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.710 kg mass, i.e., F = 6.965 N. Calculate the angular acceleration of the cylinder.

Because the bearing is thin, the moment of inertia of the bearing is essentially that of a solid cylinder
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