I need help calculating some of the following values please. PLEASE show your work!!reaction equation:MnO4− + 5 Fe2+ + 8 H+ → Mn2+ + 5 Fe3+ + 4 H2O Part 2. Determination of the Mass Percent of FeS0, • 7H,04Experimental DataSample #Pill #1Pill #21.0412g1.0393gMass of boat and ground pill. ७९2E60.6682g0.மமேகதுMass of boatInitial burette reading27.0mL28.9mLFinal burette reading44.2mL43.5mkReactionMnO, + 5 Fe2 + 8 H* → 5 Fe* + Mn²+ + 4 H,OCalculated Valuesfrom Part 1your [KMNO,l,vg =0.0114809Use%3DMass of ground pillVolume of KMNO,Moles of KMNO,Moles of Fe2+Moles of FeSO, • 7H,OMass of FeSO, • 7H,OMass % FeSO, • 7H,OAverage mass % FeSO, • 7H,OAdditional calculation (see page 4-7 and Worksheet)Average mass % FeSO, • 7H,O using zone [KMnO¸]

Given: Molarity of KMnO4 = 0.0114809 M Balanced reaction : MnO4− + 5 Fe2+ + 8 H+ → Mn2+ + 5 Fe3+ + 4…

Answered: Mass of ground pill Volume of KMNO,…

Mass of ground pill Volume of KMNO, Moles of KMNO, Moles of Fe2+ Moles of FeSO, • 7H,O Mass of FeSO, • 7H,O Mass % FeSO, • 7H,O Average mass % FeSO, • 7H,O

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter11: Intermolecular Forces And Liquids

Section11.6: Properties Of Liquids

Problem 1.2ACP

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

I need help calculating some of the following values please. PLEASE show your work!!

reaction equation:

MnO₄⁻ + 5 Fe²⁺ + 8 H⁺ → Mn²⁺ + 5 Fe³⁺ + 4 H₂O

Part 2. Determination of the Mass Percent of FeS0, • 7H,0
4
Experimental Data
Sample #
Pill #1
Pill #2
1.0412g
1.0393g
Mass of boat and ground pill
. ७९2E6
0.6682g
0.மமேகது
Mass of boat
Initial burette reading
27.0mL
28.9mL
Final burette reading
44.2mL
43.5mk
Reaction
MnO, + 5 Fe2 + 8 H* → 5 Fe* + Mn²+ + 4 H,O
Calculated Values
from Part 1
your [KMNO,l,vg =
0.0114809
Use
%3D
Mass of ground pill
Volume of KMNO,
Moles of KMNO,
Moles of Fe2+
Moles of FeSO, • 7H,O
Mass of FeSO, • 7H,O
Mass % FeSO, • 7H,O
Average mass % FeSO, • 7H,O
Additional calculation (see page 4-7 and Worksheet)
Average mass % FeSO, • 7H,O using zone [KMnO¸]

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