Answer these questions Match each P-value with the graph that displays its area without performing any calculations. Explain your reasoning. P=0.0125 and P 0.2296.(a) z= - 2.24(b) z = - 0.74GraphV displays the area for P = 0.0125 and graphV displays the area for P = 0.2296 because the P-valuetheis equal to one minusis equal tois related tois related to one minusClear allCheck answerView an exampleGet more help -Help me solve thisQuestion 18 (0/1)Question 19 (0/1)Question 20 (0/1)Question 17 (0/1)Ouestion 22 (0/1)8:0Ouestion 21 (0/166°F10/20are to searchCop Match each P-value with the graph that displays its area without performing any calculations. Explain your reasoning. P= 0.0125 and P= 0.2296.(a) z= - 2.24(b) z = - 0.74.....GraphV displays the area for P = 0.0125 and graphV displays the area for P = 0.2296 because the P-valueV theshaded area.absolute value of z.View an exampleGet more help-Clear allCheck answerHelp me solve thisQuestion 18 (0/1)Question 19 (0/1)Question 20 (0/1)Question 17 (0/1)Ouestion 22 (0/1)Ouestion 21 (0/166°Fo search近

We have given that two graphs with p-values. The shaded area is shown in the graphs.

Match each P-value with the graph that displays its area without performing any calculations. Explain your reasoning. P= 0.0125 and P= 0.2296. (a) z= - 2.24 (b) z = - 0.74 ..... Graph V displays the area for P = 0.0125 and graph V displays the area for P = 0.2296 because the P-value V the shaded area. absolute value of z.

Match each P-value with the graph that displays its area without performing any calculations. Explain your reasoning. P= 0.0125 and P= 0.2296. (a) z= - 2.24 (b) z = - 0.74 ..... Graph V displays the area for P = 0.0125 and graph V displays the area for P = 0.2296 because the P-value V the shaded area. absolute value of z.

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter7: Analytic Trigonometry

Section7.6: The Inverse Trigonometric Functions

Problem 94E

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