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Compare the cost of the two types of composite materials on the basis of their capitalized costs. Use an interest rate of 10% per year.
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- A purchase of a new machine is being evaluated. If we assume 12% annual interest, what is the Equivalent Uniform Annual Cost? Choose the nearest answer. Initial Cost $30,000 Annual Maintenance $1,500 Salvage Value $5,000 Life 6 yearsRLC Manufacturing is planning to purchase a cutting equipment. Information are as follows: Equipment 1 Equipment 2 First Cost P 12,000 P 18,000 Salvage Value P 600 P 2,000 Annual Operation P 3,200 P 2,500 Annual Maintenance P 1,200 P 1,000 Taxes & Insurance 3% 3% Life, years 10 15 Money is worth at least 16%. Which equipment should be selected? Use: Rate of Return MethodA fabrication company engaged in production with a capacity of 150, 000 pieces per year. But, it is just operating at 70% of its full capacity. The company has an annual income of P 250, 000.00, annual fixed cost are P 50, 000.00 and variable costs are P 1.00 per unit. How many productions of parts must be produced for break-even point? Given: Required: Solution: refer to this textbook: https://drive.google.com/file/d/1h4ra80IE8IRtYyja16iK6TtjCrTDi73j/view?usp=sharing
- A project is being considered that has a first cost of $12,500, creates $5000 in annual cost savings, requires $3000 in annual operating costs, and has a salvage value of $2000 after a project life of 3 years. If interest is 10% per year, which formula calculates the project’s present worth? (a) PW = 12,500(P/F, 10%, 1) + (− 5000 + 3000) (P/A, 10%, 3) − 2000(F/P, 10%, 3) (b) PW = − 12,500 + (5000 − 3000) (P/A, 10%, 3 ) − 2000(P/F, 10%, 3) (c) PW = 12,500(F/P, 10%, 3) + (5000 − 3000) (F/A, 10%, 3) + 2000 (d) PW = − 12, 500 + 5000(P/A, 10%, 3) − 3000 (P/A, 10%, 3) + 2000(P/F, 10%, 3)An oil company is planning to install a new 80 mm pipeline to connect storagetanks to a processing plant 1500 m away. The connection will be needed for theforeseeable future. Refer to their costs incurred below:initial cost: RM15,000service life: 12 yearssalvage value: RM200one-off saving in year 8: RM 300annual profit: RM400annual pump operation hours: 450 hourspump cost per hours: RM2.50Calculate the single project evaluation using Benefit Cost Ratio PW analysismethod, which is preferred if the MARR is 7%. Draw the cashflow diagram.5-27image If produced by Method A, a product’s initial capital cost will be $100,000, its annual operating cost will be $20,000, and its salvage value after 3 years will be $20,000. With Method B there is a first cost of $150,000, an annual operating cost of $10,000, and a $50,000 salvage value after its 3-year life. Based on a present worth analysis at a 15% interest rate, which method should be used?
- Calculate the future worth (FW) at 10% of a project that will save $25K per year for 20 years. The first cost is $120K, and the salvage value is $20K. Compare this with the PW and the EAW. (Please show the process and solution ty.)ENGINEERING ECONOMICSMenchie bought his brother a laptop 5 years ago which has a cost of around 25,000PhP. The laptop’s life span willlast until 5 years. She has a friend which is a computer technician who advised her that the laptop’s life span couldextend until 10 years if she could spend semi-annual maintenance of 100Php with a 10Php increase rate startingthe next period of maintenance inspection. How much is the total future cost assuming that the money will havea rate of 2% compounded semi-annually if she decided to enjoy using her laptop beyond the expected life spanupon purchasing?Mr Dela Cruz is going to buy a new machine for manufacturing its product: Machine A has a first cost of P50,000; annual maintenance P6,000; life 12 years and salvage value of P2,000. Machine B has a first cost of P140,000; annual maintenance P2,500, life 36 years and salvage value P10,000. Money is worth 9% .Compute the annual cost of machine B choices: A. P551 B. P2,500 C. P15,651 D. P7,550 COMPELETE SOLUTION
- Consider your self as a businessman, you owned 5 storey building with a total of 35-unit apartment near at the downtown area of Davao City. You felt that because the location of the apartment will be occupied 95% at all time. You desires a rate of return 30%. Other pertinent data are the following: Land investment - 8,000,000.00 Building investment - 20,000,000.00 Study period - 30 yrs Cost of the land after 30 yrs - 25,000,000.00 Cost of the building after 30 yrs - 5,000,000.00 Rent per unit per month - 7,500.00 Upkeep per unit per year - 1,500.00 Property Taxes - 1% Insurance - 0.5% Is this a good investment? And what is the Payback period of investment? Note: use all the method.Two lathes are being considered in the manufacture of certain machine parts. Data is given below, all cost in peso: LATHE A LATHE B First Cost 40,000 56,000 Salvage Value 5,000 7,000 Annual Maintenance 2,000 2,800 Operation, Cost/hour 4 3.5 Life, in years 10 12 Time per part (hours) 0.40 0.25 REQUIRED: Determine the number of machine parts/year that could be produced so that 2 lathes will be equally economical if the MARR is 18%. Use AWM If the number of parts is 10,000 units, which lathe will you recommend? Use ROR If the number of parts is 10,000 units, which lathe will you recommend? Use PWM If the number of parts is 10,000 units, which lathe will you recommend? Use EUACIPS Corp. will upgrade its package-labeling machinery. It costs $850,000 to buy the machinery and have it installed. Operation and maintenance costs, which are $11,000 per year for the first 3 years, increase by $1000 per year for the machine’s 10-year life. The machinery has a salvage value of 12% of its initial cost. Interest is 25%. What is the future worth of cost of the machinery? dont use excel. dont write answer in a paper becouse of handwriting. thanks