Math 150 PO1 Homework: HW 2.6 Part 1 Applications of Derivatives Question 8, Instructor-created question The height (feet) of a ball launched in the air t seconds after it is launched is given by: f(t) = - - 16 + 298t + 22. The velocity of the ball when at a height of 120 feet is ft/sec. If necessary, round to two decimal places. If there is more than one correct answer, separate them with commas.

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Chapter4: Complex Numbers
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Math 150 PO1
Homework: HW 2.6 Part 1 Applications of
Derivatives
Question 8, Instructor-created question
>
The height (feet) of a ball launched in the air t seconds after it is launched is given by:
f(t) = – 16t + 298t + 22.
The velocity of the ball when at a height of 120 feet is
ft/sec.
If necessary, round to two decimal places. If there is more than one correct answer, separate them with commas.
Transcribed Image Text:Math 150 PO1 Homework: HW 2.6 Part 1 Applications of Derivatives Question 8, Instructor-created question > The height (feet) of a ball launched in the air t seconds after it is launched is given by: f(t) = – 16t + 298t + 22. The velocity of the ball when at a height of 120 feet is ft/sec. If necessary, round to two decimal places. If there is more than one correct answer, separate them with commas.
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height of ball is given by f(t)=-16t2+298t+22

we want to find velocity of ball at height 120 feet

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