Memory 12200 12201 12202 12203 12204 Content %3D AA EE FF 22 What result is produced in the destination operand by execution the following instruction? a- LEA SI,(DI+BX+5] b-LDS SI,.[200]
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- instruction is in the first picture please give me only implementation of int L1lookup(u_int32_t address) and int L2lookup(u_int32_t address) cacheSim.h #include<stdlib.h>#include<stdio.h>#define DRAM_SIZE 1048576typedef struct cb_struct {unsigned char data[16]; // One cache block is 16 bytes.u_int32_t tag;u_int32_t timeStamp; /// This is used to determine what to evict. You can update the timestamp using cycles.}cacheBlock;typedef struct access {int readWrite; // 0 for read, 1 for writeu_int32_t address;u_int32_t data; // If this is a read access, value here is 0}cacheAccess;// This is our dummy DRAM. You can initialize this in anyway you want to test.unsigned char * DRAM;cacheBlock L1_cache[2][2]; // Our 2-way, 64 byte cachecacheBlock L2_cache[4][4]; // Our 4-way, 256 byte cache// Trace points to a series of cache accesses.FILE *trace;long cycles;void init_DRAM();// This function print the content of the cache in the following format for an N-way cache with M Sets// Set 0…In MARIE assembly language: / This program reads a decimal array and outputs each/ number. The array is terminated with a zero./ Add the decimal numbers and store in sum and display sum at the end. ORG 100Get, LoadI ptr / Load the number found at address ptr.Skipcond 400 / If it is a zero, we are done.Jump Outp / Otherwise, proceed with operation.HaltOutp, Output / Output the number.Load ptr / Move pointer to next number.Add OneStore ptrJump GetOne, Hex 0001ptr, Hex 10BArray, Dec 072Dec 011Dec 018Dec 010Dec 119Dec 032Dec 110Dec 019Dec 000 Sum, Dec 000ENDInput file sample.txt contains a hex dump of some data in the following format:<address> <byte1> <byte2> ... <byte16>Example Input File:00000000 54 68 69 73 20 69 73 20 61 6e 20 65 78 61 6d00000010 70 6c 65 20 6f 66 20 68 65 78 20 64 75 6d 70...Construct a pipeline using Ubuntu bash to discard the first column (address) and to reformat bytesinto a single column:
- Convert given code to LEGv8 code:int f, g, y //global 64-bit variablesint sum (int a, int b) { // at memory address X0+1000.return (a +b)} int main (void) // at memory address X0 + 800{f=2;g=3;y= sum (f, g);return y;}Convert this code, making valid assumptions about registers and register use. Notethat brackets and global variable declarations are not affecting the addresses of the instructionsin memory.Microprocessors I need EMU8086 - MICROPROCESSOR EMULATOR code to run all given tasks below Task 01Swap two numbers using ADD/SUB instructions only.Task 02If A, B and C are 3 variables, perform the given mathematical operation • A = C + (B – A) - 2 ;Task 03If X, Y and Z are 3 variables, then perform the given mathematical operation• Y * Y / (4 * X * Z)Task 04Perform the following arithmetic operation: 10 * 7 / (1 - 4) + 13 + 52 – 4 *1. Do the following Replace each uppercase letter in the following string by its lowercaseequivalent and print the converted string using string output function(function# 9). Use index addressing mode (use any of BX/SI/DI/BP forindexing). MSG DB “THISISCSELABASSIGNMENT$” 2. Write a program using the Loop instruction to print all letters each in a newline as follows (must print all 26 letters): ABC...YZ
- The following data segment starts at memory address 1000h (hexadecimal) .data printString BYTE "ASSEMBLY IS FUN",0 moreBytes BYTE 25(DUP)0 dateIssued DWORD ? dueDate DWORD ? elapsedTime Word ? What is the hexadecimal address of dueDate ? a. 1045h b. 1029h c.1010h d. 102DhC PROGRAMMING HELP! I tried a threaded reply and bartleby wasn't having it. Soooo: Please create the header file as specified and implement it into my script. Thank you for your help, it is seriously appreciated! The header file deals with the following instruction prompt: Find the roots of the second order nontrivial solution.D2y+a1Dy+a2 = 0 => λ 2+a1 λ +a2 = 0Create a header file for this step. I believe the portion of the script that needs to be turned into a utilized header file is located in the main() function. Thank you so much for your help, pasted is a copy of my script so far: #include <stdio.h>#include <math.h> void compute_coefficients(double lambda1, double lambda2, double *C1, double *C2, double *C_alpha, double *theta);void display_output(double lambda1, double lambda2, double C1, double C2, double C_alpha, double theta); int main(){ int a, b, c; double lambda1, lambda2, C1, C2, C_alpha, theta; printf("Enter a, b, and c where a*D2y + b*Dy + c*y =…What value will RAX contain after the following instruction executes?mov rax,44445555h
- Using the Circle class defined in Q1, the following statements are coded in the main(). Circle c1 = new Circle(); Circle c2 = new Circle(10); c1 = c2; Draw the memory allocation structure(s) for these instructions including the content values if possible.CODE IN MACHINE LANGUAGE USING LC-3 Write an assembly program to set R0=1 if there's a 5 in one of ten memory locations, starting at x3100. At the beginning of the program, set R0 = 0. If no 5 is found, it should leave R0 set to 0. Please submit your assembly program below. I will run it with my data. If a 5 is found, output the following message to the console. "A 5 was found at x31xx." 31xx is the hex address of the 5. Here is the test data I used to generate the screen print below. It is not the test data I will use to grade your project. .ORIG x3100.FILL #10.FILL #20.FILL #30.FILL #40.FILL #50.FILL #5.FILL #70.FILL #5.FILL #90.FILL #100.ENDCODE IN MACHINE LANGUAGE USING LC-3 Write an assembly program to set R0=1 if there's a 5 in one of ten memory locations, starting at x3100. At the beginning of the program, set R0 = 0. If no 5 is found, it should leave R0 set to 0. Please submit your assembly program below. I will run it with my data. Extra credit - 20 points: If a 5 is found, output the following message to the console. "A 5 was found at x31xx." 31xx is the hex address of the 5. Here is the test data I used to generate the screen print below. It is not the test data I will use to grade your project. .ORIG x3100.FILL #10.FILL #20.FILL #30.FILL #40.FILL #50.FILL #5.FILL #70.FILL #5.FILL #90.FILL #100.END