Meredith leaves the office, drives 26km due North, then turns onto a street and continues in a direction 30°N of E for 35km and finally turns onto the highway due East for 40km. What is her total displacement from the office? Displacement (vector) y-component X-component LP d2 d3 E(summation) Solutions:

Meredith leaves the office, drives 26km due North, then turns onto a street and continues in a direction 30°N of E for 35km and finally turns onto the highway due East for 40km. What is her total displacement from the office? Displacement (vector) y-component X-component LP d2 d3 E(summation) Solutions:

Name: 2. Meredith leaves the office, drives 26km due North, then turns onto
Uploaded: 2024-03-20T06:57:47.000Z
Channel: Bartleby
Description: 2. Meredith leaves the office, drives 26km due North, then turns onto a street andcontinues in a direction 30°N of E for 35km and finally turns onto the highway due Eastfor 40km. What is her total displacement from the office?Displacement (vector)d1

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter5: Displacement And Force In Two Dimensions

Section5.1: Vectors

Problem 3PP

See similar textbooks

Similar questions

(a) Repeat the problem two problems prior, but for the second leg you walk 20.0 m in a direction 40.0° north of east (which is equivalent to subtracting B from A that is, to finding R=AB ). (b) Repeat the problem two problems prior, but now you first walk 20.0 m in a direction 40.0° south of west and then 12.0 m in a direction 20.0° east of south (which is equivalent to subtracting A from B that is, to finding R=BA=R ). Show that this is the case.
Figure OQ1.13 shows two vectors D1 and D2. Which of the possibilities (a) through (d) is the vector D22D1, or (e) is it none of them? Figure OQ1.13
A hiker walks from (x1, y1) = (4.00 km. 3.00 km) to (x2, y2) = (3.00 km, 6.00 km), (a) What distance has the traveled? (b) The hiker desires to return to his starting point. In what direction should he go? (Give the angle with respect to due cast.) (See Sections 3.2 and 3.3.)
You fly 32.0 km in a straight line in still air in the direction 35.0° south of west. (a) Find the distances you would have to fly straight south and then straight west to arrive at the same point. (This determination is equivalent to finding the components of the displacement along the south and west directions.) (b) Find the distances you would have to fly first in a direction 45.0° south of west and then in a direction 45.0° west of north. These are the components of the displacement along a different set of axes—one rotated 450°.
1A) Saanich is walking around the campus. Saanich walks 2.4 km north. Saanich then makes a left turn and walks 1.45 km west. Finally, Saanich makes a right turn and walks 1.2 km north and sits on a bench. What is the magnitude and displacement of Saanich from the starting point? a) 3.9 km, 24° north of west b)5.3 km, 59° north of west c) no answer is correct d)3.9 km, 66° north of west e)5.3 km, 70° north of west 1B) Saanich drives a car of mass 1800 kg on the Ford Test Track. If the initial speed of the car is 32m/s and the track can be approximated as a circle of radius 25 m, what is the average velocity Saanich would be travelling at during a single revolution? a) 100 m/s b) zero m/s c) 44 m/s d) 26 m/s e) 32 m/s 1C) Saanich is participating in a physics lab. He fires a projectile at an angle of 47.0° off of a desk. If Saanich shoots the projectile at a speed of 25 m/s, how long does it take the projectile to reach its highest point? a) 1.7 s b) 2.9 s c) 1.9 s d) 9.8 s e)1.5 s
A sailor in a small sailboat encounters shifting winds. She sails 8.00 km south, then 15 km 30deg E of N, and then 12km 25deg N of W. Use polygon method to determine magnitude and direction of her resultant displacement.
You walk 30 m at 10 degree East of North, you then walk 40 m at 20 degree South of West. You then walk 90 m SW. What are the magnitude and direction of your resultant displacement?
1. The dog runs across the backyard lot on which a set of coordinates axes has, strangely observed, been drawn. The coordinates of the dog’s position as functions of time t are given by X = -0.35?2 + 7.5t +30 and Y = 0.25?2 – 9.5t + 26. With t in seconds and x and y in meters.(a) At t =15.0s, what is the dogs position vector ? in unit – vector notation and as magnitude and an angle. (b) The velocity ? at time t =15.0s in unit – vector notation and as magnitude and an angle. (c) Find the acceleration ? at time t = 15.0s in unit – vector notation and as magnitude and an angle.
Problem An explorer in Antarctica leaves his shelter during a whiteout. He takes 50 m northeast, next 180 m at 72° north of west, and then 150 m due south. Save the explorer from becoming hopelessly lost by giving him the displacement, calculated by using the method of components, that will return him to his shelter. Solution By vector-component approach, we list down the given in a table as follows: Given X-component (w/ sign direction) y-component (w/ sign direction) A = 50 m NE m m B = 180 m 72° NW m m C = 150 m s m m Resultant m m Thus, the magnitude of the resultant vector is R= m With a direction of o = ONW Therefore, the vector needed for him to successfully get back home is Rhome = O SE m
A sailor in a small boat encounters shifting winds. She sails 8 km south, then 15 km 30o E of N, and then 12 km 25o N of W. Use the polygon method to determine the magnitude and direction of her resultant displacement.
A novice golfer in the green takes three strokes to dunk the ball. The successful displacement of the balls are d1=4.04m to the north, d2=1.96 m northeast, and d3=1.16m at 30.0° west of south. Starting at the initial point, an expert golfer could make this hole in what single displacement. Find the magnitude and direction north of east.
A runner first runs a displacement A of 3.30 km due south, and then a second displacement B that points due east. The magnitude of the resultant displacement A + B is 5.27 km. What is the magnitude (in m) of B? What is the angle that A + B makes relative to due south? (Your answer must be a positive number from 0 to 180 degrees).