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merization rate constant is 1.5*102 L/(mol*s) at 100° C. How long would it take to prepare the polyester with the number average molecula

merization rate constant is 1.5*102 L/(mol*s) at 100° C. How long would it take to prepare the polyester with the number average molecula

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Problem 1: It is desired to prepare polyester with the number average molecular weight, Mn- 5000 g/mol by reacting of 1 mol butane-1,4 diol (HO-CH2-CH2-CH2-CH2-OH) with 1 mol of adipic acid (HOOC-CH2-CH2-CH2-CH2-COOH).

For the polymerization process value of polymerization rate constant is 1.5*102 L/(mol*s) at 100° C. How long would it take to prepare the polyester with the number average molecular weight, M, 5,000 g/mol at 100 ° C? There is no diol loss for this part of the problem. Hint: all equations for step-growth polymerization include concentrations of functional groups reacting and not concentrations of monomers.

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