Methane, CH4, effuses through a small opening in the side of a container at a rate of 1.30 x 10-8 mol/s. An unknown gas effuses through the same opening at the rate of 9.19 x 10-9 mol/s when maintained at the same temperature as methane. Which of the following could be the unknown gas? a. O2 b. Xe c. Kr d. Ne e. H2

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Asked Oct 20, 2019
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Methane, CH4, effuses through a small opening in the side of a container at a rate of 1.30 x 10-8 mol/s. An unknown gas effuses through the same opening at the rate of 9.19 x 10-9 mol/s when maintained at the same temperature as methane. Which of the following could be the unknown gas?

a. O2 b. Xe c. Kr d. Ne e. H2

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Expert Answer

Step 1

Given:

Rate of diffusion of Methane = 1.30 x 10-8 mol/s. = r1

Rate of diffusion of unknown = 9.19 x 10-9 mol/s= r2

Molar mass of Methane = 16 =M1

Molar mass of unknow = ? = M2

By calculating the molar mass of unknown we can identify the gas.

Step 2
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FROM graham law of diffusion/effusion, 1/r2 (M2/M,) Substitute the known values and simplify, (1.30 x 10)/ (9.19 x 10) = M2 /16 1.98 X 16 M2 31.80 M2

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