Methanol is used to heat food. The combustion of methanol can be described by the following thermochemical equation: 2CH3OH(I) + 3O2(8) 2CO2(3) + 4H20(g) AH° = -1199 kJ How much methanol, in grams, is needed to release 573 kJ of heat?

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Methanol is used to heat food. The combustion of methanol can be described by the following thermochemical equation:
2CH3OH() + 3O2(g) → 2CO2(g) + 4H2O(g) AH° = -1199 kJ
How much methanol, in grams, is needed to release 573 kJ of heat?
i
g of CH3OH
mass =
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Transcribed Image Text:Methanol is used to heat food. The combustion of methanol can be described by the following thermochemical equation: 2CH3OH() + 3O2(g) → 2CO2(g) + 4H2O(g) AH° = -1199 kJ How much methanol, in grams, is needed to release 573 kJ of heat? i g of CH3OH mass = eTextbook and Media Save for Later Attempts: 0 of 15 used Submit Answer ост 26
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