Mickey used R in fitting the probit model. He obtained the following values: a = 3.27 and b = 1.46. The estimated value of the LD50 is grams. A. 5.66 B. 1.18 C. 12.09 D. 15.31

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Chapter10: Statistics
Section10.1: Measures Of Center
Problem 9PPS
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WILL UPVOTE, just pls help me answer the following questions in the attached image. Pls show complete solutions and explain them. Thank you!

11.10. Mickey wanted to determine the lethal dose for rat poison. He then
observed a random sample of 350 rats equally divided among seven doses
(in grams) of rat poison. The data is given below:
Dose (in grams)
10
15
20
23828
35
50
70
90
Number of rats
50
50
50
50
50
50
50
Number of rats killed
20
26
27
36
35
41
45
Table 3.2 Transformation of percentages to probits
% 0
1
2
3
4
5
6 7 8 9
0
3.36 3.45 3.52 3.59 3.66
3.92 3.96 4.01 4.05 4.08 4.12
10
2.67 2.95 3.12 3.25
3.72 3.77 3.82 3.87
20 4.16 4.19 4.23 4.26 4.29 4.33 4.36 4.39 4.42 4.45
30 4.48 4.50 4.53 4.56 4.59 4.61 4.64 4.67
4.67 4.69 4.72
40 4.75 4.77 4.80 4.82 4.85 4.87 4.90
4.85 4.87 4.90 4.92 4.95 4.97
50 5.00 5.03 5.05 5.08 5.10 5.13 5.15 5.18 5.20 5.23
60 5.25 5.28 5.31 5.33 5.36 5.39 5.41 5.44 5.47 5.50
70 5.52 5.55 5.58 5.61 5.64 5.67 5.71 5.74 5.77 5.81
80 5.84 5.88 5.92 5.95 5.99 6.04 6.08 6.13 6.18 6.23
90 6.28 6.34 6.41 6.48 6.55 6.64 6.75
6.48 6.55 6.64 6.75 6.88 7.05 7.33
0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9
7.58 7.65 7.75 7.88 8.09
99 7.33 7.37 7.41 7.46 7.51
-
Mickey used R in fitting the probit model. He obtained the following values:
a = 3.27 and b = 1.46. The estimated value of the LD50 is
grams.
A. 5.66
B. 1.18
C. 12.09
D. 15.31
Transcribed Image Text:11.10. Mickey wanted to determine the lethal dose for rat poison. He then observed a random sample of 350 rats equally divided among seven doses (in grams) of rat poison. The data is given below: Dose (in grams) 10 15 20 23828 35 50 70 90 Number of rats 50 50 50 50 50 50 50 Number of rats killed 20 26 27 36 35 41 45 Table 3.2 Transformation of percentages to probits % 0 1 2 3 4 5 6 7 8 9 0 3.36 3.45 3.52 3.59 3.66 3.92 3.96 4.01 4.05 4.08 4.12 10 2.67 2.95 3.12 3.25 3.72 3.77 3.82 3.87 20 4.16 4.19 4.23 4.26 4.29 4.33 4.36 4.39 4.42 4.45 30 4.48 4.50 4.53 4.56 4.59 4.61 4.64 4.67 4.67 4.69 4.72 40 4.75 4.77 4.80 4.82 4.85 4.87 4.90 4.85 4.87 4.90 4.92 4.95 4.97 50 5.00 5.03 5.05 5.08 5.10 5.13 5.15 5.18 5.20 5.23 60 5.25 5.28 5.31 5.33 5.36 5.39 5.41 5.44 5.47 5.50 70 5.52 5.55 5.58 5.61 5.64 5.67 5.71 5.74 5.77 5.81 80 5.84 5.88 5.92 5.95 5.99 6.04 6.08 6.13 6.18 6.23 90 6.28 6.34 6.41 6.48 6.55 6.64 6.75 6.48 6.55 6.64 6.75 6.88 7.05 7.33 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 7.58 7.65 7.75 7.88 8.09 99 7.33 7.37 7.41 7.46 7.51 - Mickey used R in fitting the probit model. He obtained the following values: a = 3.27 and b = 1.46. The estimated value of the LD50 is grams. A. 5.66 B. 1.18 C. 12.09 D. 15.31
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