Midterm 1 June 5, 2023 10. [] A point charge produces an electric flux of 400 Nm²/C through a Gaussian sphere of radius 45.0 cm centred on the charge. What is the flux through a Gaussian sphere with a radius 90 cm that is centred on a charge twice as great? PHYS 1410 (a) 800 Nm²/C (b) 100 Nm²/C (c) 400 Nm²/C (d) 200 Nm²/C (e) 1600 Nm²/C

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Chapter6: Gauss's Law
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Problem 51P: ne electric field at 2 cm from the center of long copper rod of radius 1 cm has a magnitude 3 N/C...
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Midterm 1
10. [+] A point charge produces an electric flux of 400 Nm²/C through a Gaussian sphere of radius
45.0 cm centred on the charge. What is the flux through a Gaussian sphere with a radius 90 cm
that is centred on a charge twice as great?
PHYS 1410
(a) 800 Nm²/C
(b) 100 Nm²/C
(c) 400 Nm²/C
(d) 200 Nm²/C
(e) 1600 Nm²/C
For the next two questions, refer to Fig. 5.
TA
Region 1
TO
Region 3
Region 2
(conductor)
Figure 5: A solid conductor of radii rA (inner)
and TB (outer).
Colomb's Law
Jass sit mod
June 5, 2023
11. [**] Suppose a charge q is placed at
the origin O, and region 2 (rA <r <TB)
is a solid, neutral conductor. Which of the
following statements is true concerning the
magnitude of the electric field in region 2?
(a) E(r) = kq/r²
(b) E(r) > kq/r²
(c) E(r) < kq/r²
(d) E(r) = 0
(e) Not enough information is given to say
with certainty.
Transcribed Image Text:Midterm 1 10. [+] A point charge produces an electric flux of 400 Nm²/C through a Gaussian sphere of radius 45.0 cm centred on the charge. What is the flux through a Gaussian sphere with a radius 90 cm that is centred on a charge twice as great? PHYS 1410 (a) 800 Nm²/C (b) 100 Nm²/C (c) 400 Nm²/C (d) 200 Nm²/C (e) 1600 Nm²/C For the next two questions, refer to Fig. 5. TA Region 1 TO Region 3 Region 2 (conductor) Figure 5: A solid conductor of radii rA (inner) and TB (outer). Colomb's Law Jass sit mod June 5, 2023 11. [**] Suppose a charge q is placed at the origin O, and region 2 (rA <r <TB) is a solid, neutral conductor. Which of the following statements is true concerning the magnitude of the electric field in region 2? (a) E(r) = kq/r² (b) E(r) > kq/r² (c) E(r) < kq/r² (d) E(r) = 0 (e) Not enough information is given to say with certainty.
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