Mike is trying to determine the amount of work his experimental air compressor is doing. He finds that the amount of work done (W) depends on the rate of change in pressure created by the pump (dP/dt) with respect to time, the volume of air inside the pump (V) and the speed at which air moves out of the pump (v).Using the information provided above, determine the simplest expression that Mike can use to determine the work done by his pump that is dimensionally correct. After an initial test run Mike determines that his pump does 160 J of work (W1). Calculate the amount of work (W2) in J that Mike would expect his pump to do if its volume were 4.5 times greater. If Mike wanted to reduce the volume of his pump by a factor of 7.5, yet keep it doing the same amount of work at the same airspeed, by what numerical factor (B) would he have to increase the rate of change in pressure (dP/dt) his pump creates

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter11: Heat Transfer By Radiation
Section: Chapter Questions
Problem 11.16P
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 Mike is trying to determine the amount of work his experimental air compressor is doing. He finds that the amount of work done (W) depends on the rate of change in pressure created by the pump (dP/dt) with respect to time, the volume of air inside the pump (V) and the speed at which air moves out of the pump (v).Using the information provided above, determine the simplest expression that Mike can use to determine the work done by his pump that is dimensionally correct. After an initial test run Mike determines that his pump does 160 J of work (W1). Calculate the amount of work (W2) in J that Mike would expect his pump to do if its volume were 4.5 times greater. If Mike wanted to reduce the volume of his pump by a factor of 7.5, yet keep it doing the same amount of work at the same airspeed, by what numerical factor (B) would he have to increase the rate of change in pressure (dP/dt) his pump creates? 

dP
W =
dt
dP
dP V
W =
-Vv
W =
dt
dt v
4
dP v
dP V3
W =
W
dt V
dt v
Transcribed Image Text:dP W = dt dP dP V W = -Vv W = dt dt v 4 dP v dP V3 W = W dt V dt v
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