min zd = 2y, - y2 + 3ya 3y - 2y2 + ya = 1 Y + y2 - 2y3 s 2 -Yı +y2 - 5y3s-1 Y, sin rest. ; yz, Y3 S0 Primary problem s.a zd = 2y, - ya + 3ys 3y + y2 - y3 22 -2y1 + y2 + y3 = -1 Yi - 2y2 - 5ys s 2 Yı sin restricción y y2,Y3 S0 min zd = 2y, - y2 + 3ys 3y - 2y2 + y3 = 1 Y + y2 - 2y3 s2 -Y +y2 - 5y, s-1 Yı 20; y2, ya S0 min s.a s.a O option 1 O option 2 zd = 2y, - y2 + 3y3 3y1 - 2yz + y3 =1 Ya +y2 - 2y3 s 2 -Y +y2 - 5y, s-1 Ya sin rest. ; yz, y3 S0 min s.a Ooption 3 O None of above

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Consider the following primary problem, then check the option that is the dual of this problem:

 

zd = 2yı - y2 + 3y3
3y1 – 2y2 + y3 =1
Yı + y2 - 2y3 S 2
-Y1 +y2 - 5y3 s-1
Yı sin rest. ; y2, Y3 <0
min
Primary problem
s.a
zd = 2y1 - y2 + 3y3
3y1 + y2 - y3 2 2
-2yı + y2 + y3 =-1
Y1 - 2y2 - 5y3 s2
Yı sin restricción y y2,y3 <0
min zd = 2y1 – y2 +3y3
3y1 – 2y2 + y3 =1
min
s.a
s.a
Yı + y2 - 2y3 S 2
-Yı +y2 - 5y3 s-1
Yı 20; y2, Y3 S O
O option 1
O option 2
zd = 2y, - y2 + 3y3
3y1 – 2y2 + y3 =1
Yı + y2 - 2y3 S 2
-Yı +y2 - 5y3 s-1
Yı sin rest. ; y2, Y3 <0
min
s.a
Ooption 3
None of above
Transcribed Image Text:zd = 2yı - y2 + 3y3 3y1 – 2y2 + y3 =1 Yı + y2 - 2y3 S 2 -Y1 +y2 - 5y3 s-1 Yı sin rest. ; y2, Y3 <0 min Primary problem s.a zd = 2y1 - y2 + 3y3 3y1 + y2 - y3 2 2 -2yı + y2 + y3 =-1 Y1 - 2y2 - 5y3 s2 Yı sin restricción y y2,y3 <0 min zd = 2y1 – y2 +3y3 3y1 – 2y2 + y3 =1 min s.a s.a Yı + y2 - 2y3 S 2 -Yı +y2 - 5y3 s-1 Yı 20; y2, Y3 S O O option 1 O option 2 zd = 2y, - y2 + 3y3 3y1 – 2y2 + y3 =1 Yı + y2 - 2y3 S 2 -Yı +y2 - 5y3 s-1 Yı sin rest. ; y2, Y3 <0 min s.a Ooption 3 None of above
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