Mo Probs. 4–45/46

Q: For the beam shown below, a) Find all reaction forces. The support at C is a roller. b) Determine…

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Q: 3/2 P kN P kN/m 6 m

A: Load at free end = 1.5 x 25 = 37.5 KN Udl load of 25 kn- m For 6m length Udl is 25  So for X m…

Q: Determine the moment of a 1,300pound force applied at truss joint D about points B and C. Use…

A: Given: Determine the moment of a 1,300pound force applied at truss joint D about points B and C. Use…

Q: 12KN/m 6KN/m 20KNM 2mA 5m 3m 3m 4m A E 2.51 21

A: The three-moment equation defines the relation between bending moments at three continuous supports…

Q: 3.) The Force F produces a moment of F+B N-m clockwise at point A, and equal magnitude of moments…

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Q: Determine the magnitude and direction θ of theresultant force FR. Express the result in terms of…

A: Consider the following figure: Completing the parallelogram

Q: 2.20 Determine the moment of the 1,300# force applied at truss joint D about points B and C. Use…

A: Given,

Q: PROBLEM #1: Analyze the cantilever shown. Calculate the reactions at support. Solve the deflection…

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Q: A statically indeterminate beam is indicated in Figure Q1. Using the applied loading given,…

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Q: 75N 100N 30N/m Mp= 20N.m 10N.m=MA 2m 2m 3m 2m A B D E Figure 3. a) Determine the reaction force at B…

A: The shear force diagram shows the variation of shear force along the length of the beam.  The shear…

Q: The 3.4-KN force F is applied at point A. (a) Compute the moment of F about point O, expressing it…

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Q: M1 = 4000 N/m M2 = 9000 N/m P = 3600 N (downward) w1= 800 N/m (downward) w2 = 600 N/m (downward)…

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Q: A simply supported beam is loaded as shown. FIGURE 15 12 KN/m 10 KN/m B) 6m 3m Derive the shear…

A: we have to determine the shear function of segment AB in terms of x and moment function of segment…

Q: Determine the combined moment about O due to the weight of the mailbox and the cross member AB. The…

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Q: The 30-N force P is applied perpendicular to the portion BC of the bent bar. Determine the moment of…

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Q: For the given indeterminate beam: A 30 m B W 30 m P с 30 m D

A: Compute the end moments of given beam?

Q: Determine the moment of the 360 N force about (a) point A, (b) point B.

A: Consider the figure,

Q: The 4.6-kN force F is applied at point A. (a) Compute the moment of F about point O, expressing it…

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Q: Determine the internal shear and internal moment at point C in terms of P. Be consistent with units.…

A: Given,  Total Span of the beam = 580mm There is A point load acting at the point A.  Our aim is to…

Q: P 30 N C 1.6 m 45° B 1.6 m A The 30-N force P is applied perpendicular to the portion BC of the bent…

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Q: For the two couples acting on the beam, determine the force F if you know that the resultant couple…

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Q: /2 L/2

A: To Find :- shear and moment as function of x

Q: A beam is loaded and supported as shown. (a) Use the double-integration method to determine the…

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Q: Calculate the moment of the force P about the axis AD using (a) point D as the moment center.

A: This question Explains about the moment of the force P about the axis AD

Q: 0.57N, 2.53N 12N A 19N

A: To find -  Moment caused by the force at point A

Q: Determine (approximately) the internal moments at joint H from HG, and at joint J from JI and JK.

A: Consider the diagram of an approximate analysis the frame is as shown below

Q: 183.57 N 1.75 m A B 4.6 m Determine the moment at A in Newton-meters (N-m)

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Q: Determine the magnitude of the force F given that the moment about the axis BC is 600 N.m 4m B y F…

A: The given figure is shown below:

Q: Find the moment of the force F in the figure about the AC axis

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Q: Ex:-@ Find the END Moment by slope. deflection equation

A: Fixed End Moment:MFAB=MFBA=0MFBC=-wL212=-36×5212=-75 kN.mMFCB=wL212=36×5212=75 kN.mMCD=-36×1×0.5=-18…

Q: Express the internal moment in the cantilevered beam as a function of x. Determine the moment at 5m…

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Q: Find shear (V) (in kN) and moment (M) (in kN • m)

A: Shear force: - It is a force which acts parallel to cross section of body.

Q: Find the shear and moment equation of the figure.

A: Its not clear the scond load is 600 N or 400 NI take the second load as 600 NRA+RB=800+600=1400…

Q: Use: w = 355 N/m and d= 2.6 m. Find the Shear force at point C:

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Q: Compute the moment of the force P = 382 N in point A in N-m. Assuming Counterclockwise positive.…

A: P=382kN To find moment about point A

Q: P 30 N C 1.6 m 45° B 1.6 m A 39 The 30-N force P is applied perpendicular to the portion BC of the…

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Q: An overhang beam carries a distributed load "w" and a concentrated load "P". If the maximum negative…

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Q: Find the force in EG

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Q: Q1): Determine the moment of the force system of figure below: (a) with respect to point O. (b) with…

A: Given Data: Force F1=10 lb. Force F2=10 lb. Force F3=20 lb. Force F4=30 lb.

Q: [Q] Force p is 7000N. Force F is 5400 N. Find: (a) moment about AB. (b) moment about line connecting…

A: Solution: (a) P→=7Cos20°i^+7Sin20°j^kNF→=-5.4j^ kNMoment about ABP →AO→×BA→AO→=-8j^BA→=8Cos 30°…

Q: Determine the magnitude and direction e of the resultant force Fg. Express the result in terms of…

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Q: Compute the moment of the force P = 204 N in point A in N-m. Assuming Counterclockwise positive.…

A: P=204kN To find moment about point A

Q: Determine the moment of the force F about point P.Express the result as a Cartesian vector.

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Q: The force P is applied perpendicular to the portion BC of the bent bar. Find the moment of P about…

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Q: 2/40 The 30-N force P is applied perpendicular to the portion BC of the bent bar. Determine the…

A: Given that:

Q: Compute the moment of the 1.5kN force about point A. Use Varignon's theorem.

A: Given: The force is 1.5 kN.

Q: Compute the moment of the force P = 120 N in point A in N-m. Assuming Counterclockwise positive.…

A: P=120N To find moment about point A

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.