Modeling with periodic functions: Cyclical exponential decay. A spring is attached to the ceiling and pulled 11 cm down from equilibrium and released. After 4 seconds the amplitude has decreased to 7 cm. Also, the spring oscillates 13 times each second. Assuming that the amplitude is decreasing exponentially, below is a model for the distance, D the end of the spring is below equilibrium, in terms of seconds, t: D(t) = 11(0.89315)* . cos(26nt) . [Note: Here we define t as the number of seconds elapsed. Also, locations below the resting position have negative values for D.] 8 seconds, how far from equilibrium is the end of the spring? If your answer is a decimal, please round to no more than 3 decimal places. After t cm

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 27E
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Modeling with periodic functions: Cyclical exponential decay. A spring is
attached to the ceiling and pulled 11 cm down from equilibrium and released.
After 4 seconds the amplitude has decreased to 7 cm. Also, the spring oscillates
13 times each second. Assuming that the amplitude is decreasing exponentially,
below is a model for the distance, D the end of the spring is below equilibrium,
in terms of seconds, t:
D(t) = 11(0.89315)* . cos(26nt) .
[Note: Here we define t as the number of seconds elapsed. Also, locations below
the resting position have negative values for D.]
8 seconds, how far from equilibrium is the end of the spring?
If your answer is a decimal, please round to no more than 3 decimal places.
After t
cm
Transcribed Image Text:Modeling with periodic functions: Cyclical exponential decay. A spring is attached to the ceiling and pulled 11 cm down from equilibrium and released. After 4 seconds the amplitude has decreased to 7 cm. Also, the spring oscillates 13 times each second. Assuming that the amplitude is decreasing exponentially, below is a model for the distance, D the end of the spring is below equilibrium, in terms of seconds, t: D(t) = 11(0.89315)* . cos(26nt) . [Note: Here we define t as the number of seconds elapsed. Also, locations below the resting position have negative values for D.] 8 seconds, how far from equilibrium is the end of the spring? If your answer is a decimal, please round to no more than 3 decimal places. After t cm
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