Modify the CountByFives application so that the user enters the value to count by. Start each new line after 10 values have been displayed. public class CountByAnything { // Modify the code below public static void main (String args[]) { final int START = 5; final int STOP = 500; final int NUMBER_PER_LINE = 50; for(int i = START; i <= STOP; i += START) { System.out.print(i + " "); if(i % NUMBER_PER_LINE == 0) System.out.println(); } } }
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Modify the CountByFives application so that the user enters the value to count by. Start each new line after 10 values have been displayed.
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- Write an application that counts by five from 5 through 500 inclusive, and that starts a new line after every multiple of 50 (50, 100, 150, and so on). public class CountByFives { public static void main (String args[]) { // Write your code here } }public class Question1 {public static void main(String[] args) {double val;int counter = 0;int numIterations = 0;/*** Part a: Implement a branching condition that increases counter by 1 if val is larger than 0.5*/val = Math.random();/*** Part b: Add a loop around the code created in Part a that continues until counter equals 3.*//*** Part c: Use the variable numIterations to count how many times your loop in Part b iterates*/System.out.println("Number of Iterations until 3 random values greater than 0.5 were generated: "+ numIterations);}}JAVA PROGRAM FLAMES GAME (SEE ATTACHED PHOTO FOR THE PROBLEM AND EXAMPLE) Implement the method interface Flames in has the following methods: public int countLetters(String name1, String name2); - this method returns the total leftover letters between name1 and name2 public char flames(int numLetters); - this method returns the letter equivalent to the numLetters - example if numLetters is 10 is will return the letter 'M' public String letterEquivalent(char flames); -returns the String equivalent of variable flames. Below is the reference for the variable flames F - Friends L - Lovers A - Affectionate M - Marriage E - Enemies S - Sweethearts
- This is the question - Write an application that accepts any number of String values from a user until they enter zzz or have entered 15 strings, and display them in ascending order. This is the code I have but it is wrong becuase I didn't get a single check right - import java.util.*; public class StringSort2 { public static void main(String[] args) { // Write your code here Scanner sc = new Scanner(System.in); String s = ""; System.out.print(""); ///loop works until string input is zzz or string length is greater than 15 while (true){ String input = sc.nextLine(); if(input.equalsIgnoreCase("zzz") || input.length()>15) break; s=input; } } }// Application allows user to enter a series of words // and displays them in reverse order import java.util.*; public class DebugEight4 { publicstaticvoidmain(String[] args) { Scanner input =newScanner(System.in); int x =0, y; String array[] =newString[100]; String entry; finalString STOP =XXX; StringBuffer message =new StringBuffer("The words in reverse order are\n"); System.out.println("Enter any word\n" + "Enter + STOP + when you want to stop"); entry = input.next(); while(!(entry.equals(STOP))) { array[x] = entry; ++x; System.out.println("Enter another word\n" + "Enter "+STOP+" when you want to stop"); entry = input.next(); } for(y = x -1; y >0; ++y) { message.append(array[y]); message.append("\n"); } System.out.println(message) }Multiples(): Takes an int (n) as parameter and prints first 10 multiples n in a single line using for loop. Example: 5 5,10,15,20,25,30,35,40,45,50 class Main {public static void main(String[] args) {}}
- Java Program Prime Number List Use the isPrime method that you wrote in Programming Challenge 13 in a program that prompts the user to enter an integer number, then displays all prime numbers less than the user number separated by a space. Enter a number: \n10ENTER2 3 5 7 Test Case 2 Enter a number: \n100ENTER2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97Java, the user selects an item from the text files ranging 1-15, repeats the loop until 'q'. the program provides a list of what they ordered including discounts, then calculates the total bill and how much they saved. The bottom is my the code I'm working on class BillProcessor {public static void prepareBill(LinkedHashMap<String, Integer> purchases, LinkedHashMap<String,Double>items,LinkedHashMap<String,String> sales, ArrayList<String> itemNames){double totalCost, totalDiscount, actualCost, discount; //note actualCost is the price of a single itemtotalCost = 0.00;totalDiscount = 0.00;actualCost = 0.00;discount = 0.00;for(Map.Entry<String,Integer>set: purchases.entrySet()) {if (sales.get(set.getKey()) != null) {if (sales.get(set.getKey()).equals("bogo") == true) {actualCost = set.getValue() * items.get(set.getKey());totalCost += actualCost;System.out.println("Item Name : " + set.getKey() + "\tItem Quantity(bogo) : " + (set.getValue() * 2 + "\tItem Cost :…ntegers outerRange and innerRange are read from input. Complete the outer while loop so the inner loop executes (outerRange + 1) * innerRange times. Ex: If the input is 6 5, then the output is: Inner loop ran 35 times import java.util.Scanner; public class LoopCounter { public static void main (String[] args) { Scanner scnr = new Scanner(System.in); int outerRange; int innerRange; int count; int i; int j; outerRange = scnr.nextInt(); innerRange = scnr.nextInt(); count = 0; i = 0; while (/* Your code goes here */) { j = 0; while (j < innerRange) { ++count; ++j; } ++i; } System.out.println("Inner loop ran " + count + " times"); } }
- This is the question - Write an application that counts the total number of spaces contained in a quote entered by the user. This is the code I have. The issue it seems to be counting like: "The number of spaces is 0 The number of spaces is 0 The number of spaces is 0 The number of spaces is 1 The number of spaces is 1 The number of spaces is 1", rather than just saying it once with the final number of spaces. This is my code - import java.util.*; public class CountSpaces2 { public static void main(String[] args) { // Write your code here Scanner input = new Scanner(System.in); int i; String quote; System.out.println("Please enter your quote "); quote = input.nextLine(); int numSpaces=0; for(i=0; i<quote.length();i++) { char ch=quote.charAt(i); if(ch == ' ') numSpaces++; System.out.println("The number of spaces is " +numSpaces); } } }Lab2.java contains the following code: public final class Lab2 { /** * This is empty by design, Lab2 cannot be instantiated */ private Lab2() { // empty by design } /** * Returns the sum of a consecutive set of numbers from <code> start </code> to <code> end </code>. * * @pre <code> start </code> and <code> end </code> are small enough to let this * method return an int. This means the return value at most requires 4 bytes and * no overflow would happen. * * @param start is an integer number * @param end is an integer number * @return the sum of start + (start + 1) + .... + end */ public static int sum(int start, int end) { //Insert your code here and change the return statement to fit your implementation. return 0; } /** * This method creates a string using the given char * by repeating the character <code> n </code> times. * * @param first is…(in java) add a part where you print user information and update the continue watching list in program 2 Program 1: class Netflix {public String movies[] = new String[10];public String trendingTop5[] = new String[5];public String continueWatching[] = new String[5];public String username;public String password;private boolean isAuthenticated;public double balance;public int subscriberSinceYear;public void logininfo() {Scanner input = new Scanner(System.in);System.out.println("Enter the username");String username = input.nextLine();System.out.println("Enter the password");String password = input.nextLine();boolean isAuthenticated = true;System.out.println(isAuthenticated + " , You have successfully logged in ");System.out.println();}public void trendingList() {Scanner input = new Scanner(System.in);String[] items = new String[5];System.out.println("Enter the top 5 trending item of the week");int i;for (i = 0; i < 5; ++i) {items[i] =…