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Computer Science
-Modify this program to ask the enter the employees' information in order of last name, first name, number of hours, hourly rate, and if they are a cyber sec or computer sci major or both -To ask the user to enter the info, ask  "Enter the info of ten employees as shown: Last Name, First Name, # of hours worked, hourly rate and if they are a cyber sec or computer sci major or both" -Have the calculations and amount the same as shown in the program and have it printed to the terminal and in the employee.txt file -The calculations should be the hours x # of hours worked, plus 1000 if they are a cyber sec or computer sci major and 2000 if they are both.  -An example of the output is in the images   #include using namespace std;   struct Employee {     string firstName;     string lastName;     int numOfHours;     float hourlyRate;     char major[2];     float amount;     Employee* next; };   void printRecord(Employee*); void appendNode(Employee*&, Employee*);   int main() {     const int NumOfEmp = 10;       Employee* head = nullptr;     Employee* newNode;       string firstNames[] = {"John", "Jane", "Mary", "Mike", "Sarah", "David", "Emily", "Alex", "Ethan", "Olivia"};     string lastNames[] = {"Smith", "Johnson", "Williams", "Jones", "Brown", "Garcia", "Miller", "Davis", "Rodriguez", "Martinez"};     int numOfHours[] = {40, 35, 42, 37, 39, 41, 38, 36, 43, 34};     float hourlyRate[] = {20.0, 22.5, 21.0, 22.0, 20.5, 23.0, 22.0, 21.5, 23.5, 20.0};     char comp_sci[] = {'Y', 'N', 'Y', 'Y', 'N', 'Y', 'N', 'Y', 'N', 'Y'};     char comp_sec[] = {'N', 'N', 'Y', 'Y', 'Y', 'N', 'Y', 'Y', 'N', 'N'};     cout<firstName = firstNames[i];         newNode->lastName = lastNames[i];         newNode->numOfHours = numOfHours[i];         newNode->hourlyRate = hourlyRate[i];         newNode->major[0] = comp_sci[i];         newNode->major[1] = comp_sec[i];           newNode->amount = newNode->numOfHours * newNode->hourlyRate;           if (newNode->major[0] == 'Y' || newNode->major[1] == 'Y') {             newNode->amount = newNode->amount + 1000;         }         if (newNode->major[0] == 'Y' && newNode->major[1] == 'Y') {             newNode->amount = newNode->amount + 2000;         }               newNode->next = nullptr;           appendNode(head, newNode);                   printRecord(newNode);     }     ofstream outfile("Employee.txt");     if (!outfile) {         cerr << "Error: Output file could not be opened." << endl;         return 1;     }       outfile<lastName << setw(15) << current->firstName << setw(12) << current->numOfHours << setw(20)         << current->hourlyRate << setw(20) << current->amount << setw(20) << current->major[0]<major[1] << endl;         current = current->next;     }       outfile.close();       return 0; }       void printRecord(Employee* e) {         cout << left << setw(15) << e->lastName << setw(15) << e->firstName << setw(12)     <numOfHours<hourlyRate<amount     << setw(10) << e->major[0] << setw(10) << e->major[1]<< endl; }   void appendNode(Employee*& head, Employee* newNode) {     if (head == nullptr) {         head = newNode;     }     else {         Employee* current = head;         while (current->next != nullptr) {             current = current->next;         }         current->next = newNode;     } }

-Modify this program to ask the enter the employees' information in order of last name, first name, number of hours, hourly rate, and if they are a cyber sec or computer sci major or both -To ask the user to enter the info, ask  "Enter the info of ten employees as shown: Last Name, First Name, # of hours worked, hourly rate and if they are a cyber sec or computer sci major or both" -Have the calculations and amount the same as shown in the program and have it printed to the terminal and in the employee.txt file -The calculations should be the hours x # of hours worked, plus 1000 if they are a cyber sec or computer sci major and 2000 if they are both.  -An example of the output is in the images   #include using namespace std;   struct Employee {     string firstName;     string lastName;     int numOfHours;     float hourlyRate;     char major[2];     float amount;     Employee* next; };   void printRecord(Employee*); void appendNode(Employee*&, Employee*);   int main() {     const int NumOfEmp = 10;       Employee* head = nullptr;     Employee* newNode;       string firstNames[] = {"John", "Jane", "Mary", "Mike", "Sarah", "David", "Emily", "Alex", "Ethan", "Olivia"};     string lastNames[] = {"Smith", "Johnson", "Williams", "Jones", "Brown", "Garcia", "Miller", "Davis", "Rodriguez", "Martinez"};     int numOfHours[] = {40, 35, 42, 37, 39, 41, 38, 36, 43, 34};     float hourlyRate[] = {20.0, 22.5, 21.0, 22.0, 20.5, 23.0, 22.0, 21.5, 23.5, 20.0};     char comp_sci[] = {'Y', 'N', 'Y', 'Y', 'N', 'Y', 'N', 'Y', 'N', 'Y'};     char comp_sec[] = {'N', 'N', 'Y', 'Y', 'Y', 'N', 'Y', 'Y', 'N', 'N'};     cout<firstName = firstNames[i];         newNode->lastName = lastNames[i];         newNode->numOfHours = numOfHours[i];         newNode->hourlyRate = hourlyRate[i];         newNode->major[0] = comp_sci[i];         newNode->major[1] = comp_sec[i];           newNode->amount = newNode->numOfHours * newNode->hourlyRate;           if (newNode->major[0] == 'Y' || newNode->major[1] == 'Y') {             newNode->amount = newNode->amount + 1000;         }         if (newNode->major[0] == 'Y' && newNode->major[1] == 'Y') {             newNode->amount = newNode->amount + 2000;         }               newNode->next = nullptr;           appendNode(head, newNode);                   printRecord(newNode);     }     ofstream outfile("Employee.txt");     if (!outfile) {         cerr << "Error: Output file could not be opened." << endl;         return 1;     }       outfile<lastName << setw(15) << current->firstName << setw(12) << current->numOfHours << setw(20)         << current->hourlyRate << setw(20) << current->amount << setw(20) << current->major[0]<major[1] << endl;         current = current->next;     }       outfile.close();       return 0; }       void printRecord(Employee* e) {         cout << left << setw(15) << e->lastName << setw(15) << e->firstName << setw(12)     <numOfHours<hourlyRate<amount     << setw(10) << e->major[0] << setw(10) << e->major[1]<< endl; }   void appendNode(Employee*& head, Employee* newNode) {     if (head == nullptr) {         head = newNode;     }     else {         Employee* current = head;         while (current->next != nullptr) {             current = current->next;         }         current->next = newNode;     } }

Fundamentals of Information Systems
Fundamentals of Information Systems
9th Edition
ISBN:9781337097536
Author:Ralph Stair, George Reynolds
Publisher:Ralph Stair, George Reynolds
Chapter7: Knowledge Management And Specialized Information Systems
Section: Chapter Questions
Problem 7DQ
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-Modify this program to ask the enter the employees' information in order of last name, first name, number of hours, hourly rate, and if they are a cyber sec or computer sci major or both
-To ask the user to enter the info, ask 
"Enter the info of ten employees as shown: Last Name, First Name, # of hours worked, hourly rate and if they are a cyber sec or computer sci major or both"
-Have the calculations and amount the same as shown in the program and have it printed to the terminal and in the employee.txt file
-The calculations should be the hours x # of hours worked, plus 1000 if they are a cyber sec or computer sci major and 2000 if they are both. 
-An example of the output is in the images
 
#include<bits/stdc++.h>
using namespace std;

 

struct Employee {
    string firstName;
    string lastName;
    int numOfHours;
    float hourlyRate;
    char major[2];
    float amount;
    Employee* next;
};

 

void printRecord(Employee*);
void appendNode(Employee*&, Employee*);

 

int main() {
    const int NumOfEmp = 10;

 

    Employee* head = nullptr;
    Employee* newNode;

 

    string firstNames[] = {"John", "Jane", "Mary", "Mike", "Sarah", "David", "Emily", "Alex", "Ethan", "Olivia"};
    string lastNames[] = {"Smith", "Johnson", "Williams", "Jones", "Brown", "Garcia", "Miller", "Davis", "Rodriguez", "Martinez"};
    int numOfHours[] = {40, 35, 42, 37, 39, 41, 38, 36, 43, 34};
    float hourlyRate[] = {20.0, 22.5, 21.0, 22.0, 20.5, 23.0, 22.0, 21.5, 23.5, 20.0};
    char comp_sci[] = {'Y', 'N', 'Y', 'Y', 'N', 'Y', 'N', 'Y', 'N', 'Y'};
    char comp_sec[] = {'N', 'N', 'Y', 'Y', 'Y', 'N', 'Y', 'Y', 'N', 'N'};
    cout<<left<<setw(15) <<"Last Name"<<setw(15) <<"First Name"<<setw(12) <<"# of Hours"<<setw(12) <<"Hourly Rate"
    << setw(10) << "Amount"<< setw(10)<<"Comp Sci" << setw(20) << "Comp Sec" << endl;
    for (int i = 0; i < NumOfEmp; i++) {
        newNode = new Employee;

 

        newNode->firstName = firstNames[i];
        newNode->lastName = lastNames[i];
        newNode->numOfHours = numOfHours[i];
        newNode->hourlyRate = hourlyRate[i];
        newNode->major[0] = comp_sci[i];
        newNode->major[1] = comp_sec[i];

 

        newNode->amount = newNode->numOfHours * newNode->hourlyRate;

 

        if (newNode->major[0] == 'Y' || newNode->major[1] == 'Y') {
            newNode->amount = newNode->amount + 1000;
        }
        if (newNode->major[0] == 'Y' && newNode->major[1] == 'Y') {
            newNode->amount = newNode->amount + 2000;
        }

 

   
        newNode->next = nullptr;

 

        appendNode(head, newNode);

 

       
        printRecord(newNode);
    }



    ofstream outfile("Employee.txt");
    if (!outfile) {
        cerr << "Error: Output file could not be opened." << endl;
        return 1;
    }

 

    outfile<<left<<setw(15) <<"Last Name"<<setw(15) <<"First Name"<<setw(12) <<"# of Hours"<<setw(20) <<"Hourly Rate"
    << setw(20) << "Amount"<< setw(20)<<"Comp Sci" << setw(20) << "Comp Sec" << endl;
    Employee* current = head;
    while (current != nullptr) {
        outfile << left << setw(15) << current->lastName << setw(15) << current->firstName << setw(12) << current->numOfHours << setw(20)
        << current->hourlyRate << setw(20) << current->amount << setw(20) << current->major[0]<<setw(25)<< setw(25) << current->major[1] << endl;
        current = current->next;
    }

 

    outfile.close();

 

    return 0;
}

 

 

 

void printRecord(Employee* e) {
   
    cout << left << setw(15) << e->lastName << setw(15) << e->firstName << setw(12)
    <<e->numOfHours<<setw(12) <<e->hourlyRate<<setw(10) <<e->amount
    << setw(10) << e->major[0] << setw(10) << e->major[1]<< endl;
}

 

void appendNode(Employee*& head, Employee* newNode) {
    if (head == nullptr) {
        head = newNode;
    }
    else {
        Employee* current = head;
        while (current->next != nullptr) {
            current = current->next;
        }
        current->next = newNode;
    }
}
 
main.cpp 1 Last Name 2 Smith 3 Johnson 4 Williams 5 Jones 6 Brown 7 Garcia 8 Miller 9 Davis 10 Rodriguez 11 Martinez 12 Smith Johnson Williams Run ✪ Debug Employee.txt: Jones Brown Garcia Miller Davis Rodriguez Martinez John Jane Mary Mike Sarah David Emily Alex Mary Mike ■ Stop First Name John Jane Ethan olivia Sarah David Emily Alex Ethan Olivia 40 35 42 37 39 41 38 36 43 34 Share . Program finished with exit code 0 39 41 H Save # of Hours Hourly Rate 40 35 42 37 38 36 43 34 20 22.5 21 22 20.5 23 22 {} Beautify 21.5 23.5 20 20 22.5 21 22 20.5 23 22 21.5 23.5 20 800 787.5 882 814 799.5 943 836 774 1010.5 680 Y MHMARHAMAD N Y Y N Y N Y N Y Amount 800 787.5 882 814 799.5 943 836 774 1010.5 680 input NNNNNNNNNN Y Y Y Y Y Comp Sci Y > > > > > > > > > > N Y Y N Y N Y N Y Language C++ Comp Sec N N Y Y Y Y Y N N
Transcribed Image Text:main.cpp 1 Last Name 2 Smith 3 Johnson 4 Williams 5 Jones 6 Brown 7 Garcia 8 Miller 9 Davis 10 Rodriguez 11 Martinez 12 Smith Johnson Williams Run ✪ Debug Employee.txt: Jones Brown Garcia Miller Davis Rodriguez Martinez John Jane Mary Mike Sarah David Emily Alex Mary Mike ■ Stop First Name John Jane Ethan olivia Sarah David Emily Alex Ethan Olivia 40 35 42 37 39 41 38 36 43 34 Share . Program finished with exit code 0 39 41 H Save # of Hours Hourly Rate 40 35 42 37 38 36 43 34 20 22.5 21 22 20.5 23 22 {} Beautify 21.5 23.5 20 20 22.5 21 22 20.5 23 22 21.5 23.5 20 800 787.5 882 814 799.5 943 836 774 1010.5 680 Y MHMARHAMAD N Y Y N Y N Y N Y Amount 800 787.5 882 814 799.5 943 836 774 1010.5 680 input NNNNNNNNNN Y Y Y Y Y Comp Sci Y > > > > > > > > > > N Y Y N Y N Y N Y Language C++ Comp Sec N N Y Y Y Y Y N N
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