• Mr. Muscedere is walking to Mr. Timm's house. He takes a short cut across an open field. His first displacement is 140m [E35N]. He then walks 200.0m [E]. What is Mr. Muscedere's total displacement? 47

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Chapter3: Vectors And Two-Dimensional Motion
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SPH4U-01
COHORT A
Wednesday, April 7th, 2021
Equations and Constants
F = µFn
sinA
sinB
sinC
Fnet = ma
a? = b2 + c2 – 2bccosA
a
b.
V2 = V1 + aAt
Ad
Ad = v1At + aAt
Ad = v2At - ½aAť
Vav
Ad = ½(v1 + v2)At
(v2) = (v1)² + 2aad
v²
a. =
4n?r
= 47²rf2
g = 9.81
%3D
T2
W = FAd
W = AE
1
KE =-mv2
PE = mgAy
F = kx
1
Elastic Energy =
kx2
2.
FAt = Ap
p= mv
GMm
mearth = 5.972 x 1024kg
mmoon = 7.348 x 1022kg
Nm2
G = 6.67x10-11
kg?
Te = 6378 km
I'moon
= 1737 m
kq192
Fe
= 1.67 x 10-2"kg
mproton
melectron = 9.11 x 10-31kg
r²
Nm2
9.00x109
Gelectron/proton
= +1.60x10-19C
Transcribed Image Text:SPH4U-01 COHORT A Wednesday, April 7th, 2021 Equations and Constants F = µFn sinA sinB sinC Fnet = ma a? = b2 + c2 – 2bccosA a b. V2 = V1 + aAt Ad Ad = v1At + aAt Ad = v2At - ½aAť Vav Ad = ½(v1 + v2)At (v2) = (v1)² + 2aad v² a. = 4n?r = 47²rf2 g = 9.81 %3D T2 W = FAd W = AE 1 KE =-mv2 PE = mgAy F = kx 1 Elastic Energy = kx2 2. FAt = Ap p= mv GMm mearth = 5.972 x 1024kg mmoon = 7.348 x 1022kg Nm2 G = 6.67x10-11 kg? Te = 6378 km I'moon = 1737 m kq192 Fe = 1.67 x 10-2"kg mproton melectron = 9.11 x 10-31kg r² Nm2 9.00x109 Gelectron/proton = +1.60x10-19C
• Mr. Muscedere is walking to Mr. Timm's house. He takes a short cut
across an open field. His first displacement is 140m [E35N]. He then
walks 200.0m [E]. What is Mr. Muscedere's total displacement?
스Notes
10
A ENG
202
88
%2:
Transcribed Image Text:• Mr. Muscedere is walking to Mr. Timm's house. He takes a short cut across an open field. His first displacement is 140m [E35N]. He then walks 200.0m [E]. What is Mr. Muscedere's total displacement? 스Notes 10 A ENG 202 88 %2:
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