MW (mg/mmol) Density (mg/uL) Amount used vanillin 152.15 XXXXX 400.0 mg acetic anhydride 102.09 1.08 500. 0 µL 380.0 mg 194.18 XXXXX vanillin acetate Calculate the amount of acetic anhydride that was present.
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- 1. You give your home health patient an unopened 500-mL bottle of guaifenesin and tellthem to take 2 teaspoons 4 times a day as ordered. They ask you how long the bottlewill last. 2. You are shadowing a nurse during a clinical who receives an order to adjust the infusionrate of a pump so that 1.6 mg of lidocaine are being delivered per minute. Hanging is a100 mL piggyback containing 0.4 grams lidocaine, a 0.4% solution. How many mL perhour should the piggyback be set to deliver? How long will the piggyback last? 3. Phenobarbital 180 mg/m 2 /24 hours given every eight hours is ordered for a childwhose BSA (body surface area) is 0.29 m 2 . How many mg will you need if the child willbe on the medication for 10 days? 4. You are going to mix a 1:10 bleach solution with water to make 500 mL of a 1:35 bleachsolution. How much 1:10 bleach solution should you use?(I recommend using the C1V1=C2V2 formula) 5. As a home health nurse you need to help a client make…1. Order: isoproterenol 2 mg in 500 mL D5W to infuse at 15 mL/hrPatient weight: 20 kgHow many mcg/kg/min is the patient receiving? (Round to the 2nd decimal place/hundredth placeWhat is the simplest CGS unit for "poise"?
- If a patient added a 17-g measured dose of polyethylene glycol 3350 (miralax) to 180 mL of water to use as a laxative. If the given volume of the resultant mixture was 195.6 mL. Now, determine the apparent density of polyethylene glycol 3350 and the specific gravity of the mixture.Use this video to answer the questions: https://www.youtube.com/watch?v=BocfSXdbaU01. A 25-mL specific gravity bottle was found to weigh 46.05 g when filled with water, and 52.93 g when filled with the ophthalmic solution. If the empty specific gravity bottle weighs 21.04 g, what is the specific gravity of the ophthalmic solution? a 0.784 b 0.870 c 1.149 d 1.275
- Let me tell you about their task: The students were provided with 5 drinks (sports/soft drinks) and they were asked to determine the glucose concentration in these drinks in the units of g/100mL. (Why these units? Well, once the students have the concentrations in g/100mL they will be able to compare their values with the nutritional values given on the drink bottles’ labels). The samples of the five drinks were all diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for the students is that the dilution factor will have to be taken into consideration in their calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). The students decided to save time and form five groups where each group was…There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…
- 19 g of unknown organic sample was dissolve in 640 mL of Dicloromethane (DCM). The boiling point of benzene was increased by 3.78oC. Determine the molecular weight of the unknown sample? Kb of DCM = 2.42oC/m Bb of benzene = 39.6 oC density of benzene = 1.33 g/mL at 25 °C Round your answer to the nearest whole number, no units required.In the determination of the concentration of chloride ion in water five experiments were done: 254.3 ppm, 254.7 ppm, 249.9 ppm, 252.5 ppm, and 253.4 ppm. What is the relative average deviation of this experiment? (ppm=mg/L1)The fat content of 10 g of commercial ice cream was determined by the Mojonnier method. The weights of the extracted fat after the second extraction and the third extraction were 1.30 and 1.36 g, respectively. How much of fat, as percentage of the total, was extracted during the third extraction?