There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels).The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink).You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar).Glucose Concentration in mM of drink = 2.500 mMFrom here, you need to convert the concentration of the drink from mM of the diluted drink into g/100mL of the undiluted drink.Convert the experimental glucose concentration (mentioned above) from mM (millimolar) to g/100 mL.Make sure to: Take the 1/100 dilution factor into considerationMolarity (M) will open the doors for you to get to mass in g.Once at M assume 1L of solution. (this will help you when converting from M to moles)You will also need to calculate the molar mass of glucose which has the formula C6H12O6There are 5 steps in total Example of the dilution of Drink #1 to give you a visual idea of this dilution stepSome volume was transferred from Drink #1 into the tube andthe volume was diluted 1/100Students used thisdiluted drink toperform theirexperiment.Tube containing 1/100 dilution ofdrink #1.

Answered: Image /qna-images/answer/4c2a8290-a704-42f3-a785-842b00f561f8.jpg

Answered: Example give lon step Some volume was…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter13: The Chemistry Of Solutes And Solutions

Section13.7: Colligative Properties Of Solutions

Problem 13.17CE

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There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels).
The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink).
You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar).

Glucose Concentration in mM of drink = 2.500 mM

From here, you need to convert the concentration of the drink from mM of the diluted drink into g/100mL of the undiluted drink.

Convert the experimental glucose concentration (mentioned above) from mM (millimolar) to g/100 mL.

Make sure to:

Take the 1/100 dilution factor into consideration
Molarity (M) will open the doors for you to get to mass in g.
Once at M assume 1L of solution. (this will help you when converting from M to moles)
You will also need to calculate the molar mass of glucose which has the formula C₆H₁₂O₆
There are 5 steps in total

Example of the dilution of Drink #1 to give you a visual idea of this dilution step
Some volume was transferred from Drink #1 into the tube and
the volume was diluted 1/100
Students used this
diluted drink to
perform their
experiment.
Tube containing 1/100 dilution of
drink #1.

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