N2(g) + 3H2(g) → 2NH3(g)ΔH = -92.2 kJ
H2(g) + Cl2(g) → 2HCl(g)ΔH = -184.7 kJ
N2(g) + 4H2(g) + Cl2(g) → 2NH4Cl(s)ΔH = -628.9 kJ
Find the ΔH of the following reaction:
| NH3(g) + HCl(g) → NH4Cl(s) |
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